You need to use the distance formula
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
so the distance between points (5,-2) and (-3,8) is
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which won't simplify so it stays as is
Answer:
<u>Given rhombus ABCD with</u>
- m∠EAD = 67°, CE = 5, DE = 12
<u>Properties of a rhombus:</u>
- All sides are congruent
- Diagonals are perpendicular
- Diagonals are angle bisectors
- Diagonals bisect each other
<u>Solution, considering the above properties</u>
- 1. m∠AED = 90°, as angle between diagonals
- 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
- 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
- 4. AE = CE = 5, as E is midpoint of AC
- 5. BE = DE = 12, as E is midpoint of BD
Answer:
Step-by-step explanation:
23 hundredths = 0.23 = 2.3 * 10⁻¹
Answer:
The sets of values that correctly completes the t-chart are:
7, -1, 7
Hence, option B is true.
Step-by-step explanation:
Given the equation
y = 2x² - 1
FOR x = -2
substitute x = -2 in the equation
y = 2x² - 1
y = 2(-2)² - 1
y = 8 - 1
y = 7
FOR x = 0
substitute x = 0 in the equation
y = 2x² - 1
y = 2(0)² - 1
y = -1
FOR x = 2
substitute x = 2 in the equation
y = 2x² - 1
y = 2(2)² - 1
y = 8 - 1
y = 7
Thus, the t-chart becomes:
x y
-2 7
0 -1
2 7
Thus, the sets of values that correctly completes the t-chart are:
7, -1, 7
Hence, option B is true.
91.6 solving for m in the first equation m=8.3repeating so 11 time 8.3repeating.