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2 years ago

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A school purchases boxes of candy bars. Each box contains 23 candy bars. Each box costs $10. How much does the school have to ch

arge for each candy bar to make a profit of $70 per box? Write an equation where crepresents the cost of a candy bar and solve.

1 answer:

anygoal [31]2 years ago

7 0

Answer:

23 * 3.50$ = 80.50$ - 10$=70.50$

Step-by-step explanation:

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Answer:

Perimeter of polygon B = 80 units

Step-by-step explanation:

Since both polygons are similar, their corresponding sides and perimeters are proportional. Knowing this we can setup a proportion to find the perimeter of polygon B.

$\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}$

Let $x$ be the perimeter of polygon B. We know from our problem that the side of polygon A is 24, the side of polygon B is 15, and the perimeter of polygon A is 128.

Let's replace those value sin our proportion and solve for $x$ :

$\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}$

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$x=\frac{128*15}{24}$

$x=\frac{1920}{24}$

$x=80$

We can conclude that the perimeter of polygon B is 80 units.

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Answer:

Step-by-step explanation:

The third quartile is at 75% of total of number of students.

So percentage score great or equal to this is 25%.

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Anna11 [10]

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