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Naya [18.7K]
3 years ago
15

What is the length of Line segment B C? 9 units 11 units 15 units 16 units

Mathematics
2 answers:
Ivahew [28]3 years ago
8 0

Answer:

its 15

Step-by-step explanation:

denpristay [2]3 years ago
3 0

Answer:

15 units

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

In the right triangle ABC

Applying the Pythagorean Theorem

AB^2=AC^2+BC^2

we have

AB=17\ units\\AC=8\ units

substitute the given values

17^2=8^2+BC^2

solve for BC

289=64+BC^2\\BC^2=289-64\\BC^2=225\\BC=15\ units

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Answer:

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Step-by-step explanation:

expand by logarithms

10^x=5

=log(10^x)=log(5)

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x.l =log(5)

multiple bothside by 1

x=log(5)

x=0.6989709

6 0
3 years ago
Solve -11 &gt; -1 - 2x<br> solve your answer step by step
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3 years ago
What is the answer and could you explain
pishuonlain [190]
16 different combinations. There are 8 sections on the spinner and 2 sides on a coin. 8 combinations for heads and 8 for tails, which equals 16.

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3 0
3 years ago
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Help with geometry..need help...if any of you is good with geometry
aev [14]

Answer: For the first image, D will be the correct answer. For the second image, A will be the correct answer.

Step-by-step explanation:

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In the second image, a reflection just describes a flip over some line, known as the line of reflection. We change the point's signs depending on the line of symmetry we are given when reflecting (in this case, the y axis). Reflecting the trapezoid over the y axis will result in a change of signs of the x values of the given points. Point A of the trapezoid is located on coordinate (-2,2), after the reflection, it will be located on point (2,2). Points B will reflect from point (-1,2) to point (1,2). Point C will reflect from (-1,1) to (1,1). Finally, point D will reflect from point (-3,1) to (3,1). After this reflection, we have to perform the same one except only the y values of our coordinates will change because we are reflecting over the x axis. After you graph the trapezoid from the previous reflection, do the same thing by just changing the y values of the coordinates to get your desired image.

3 0
3 years ago
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Find the area of the shaded portion of the figure. Each vertex of square ABCD is at the center of a circle. Round your answer to
IrinaK [193]

<u>Given:</u>

Each circle has a diameter of 2 inches each.

The outer square has a side length of 4 inches and the square ABCD has a side length of 2 inches.

<u>To find:</u>

The area of the shaded region.

<u>Solution:</u>

Each circle has a diameter of 2 inches. The square ABCD is at the center of each circle so it has a side length of 1 inch.

To determine the area of the shaded region, we subtract the area of the quarter-circles in the square ABCD from the area of the square ABCD.

The area of a quarter-circle =\frac{\pi r^{2} }{4} .

All the quarter-circles have a radius of 1 inch.

The area of 1 quarter-circle =\frac{\pi r^{2} }{4} = \frac{\pi (1^{2}) }{4} = \frac{3.1415}{4} .

The area of 4 quarter-circles =4(\frac{3.1415}{4}) = 3.1415.

So the area of the quarter-circles in the square ABCD is 3.1514 square inches.

The area of a square = a^{2} .

The area of square ABCD =2^{2} =4.

The area of the shaded region =4-3.1415=0.8585.

The area of the shaded region is 0.8585 square inches.

3 0
3 years ago
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