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zlopas [31]
3 years ago
15

Simplify by combining like terms 5x+3y+3x

Mathematics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

8x+3y

Step-by-step explanation:

1. Find like terms: 5x and 3x share the same constant "x" so you can combine them. There is nothing to combine with the 3y since there is no other term with the constant "y".

2. Rearrange to make it easier to see: 5x+3x+3y

3. Add the 5x and 3x: 8x+3y

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If the point (b,15) lies on the straight line with equation Y=5x fonde the value of b ?
Andrej [43]

Answer:

b = 3

Step-by-step explanation:

Substitute the y- coordinate 15 into the equation , that is

15 = 5x ( divide both sides by 5 )

3 = x

This is the x- coordinate of the point , so b = 3

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Li’s recipe uses 3 2/3 cups of flour. He plans to make 4 batches. How much flour will li need. I need help on finding out what t
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14 and 2/3rd cups of flour for 4 batches

Step-by-step explanation:

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4 years ago
Roshanay makes turkey sandwiches for a family reunion. He purchases 84 ounces of sliced turkey for $26.88. What is the unit cost
vladimir2022 [97]

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Step-by-step explanation:

5 0
3 years ago
you drop a ball from a height of 98 feet. at the same time, your friend throws a ball upward. the polynomials represent the heig
Ostrovityanka [42]

a) h_0 -u_y t

b) See interpretation below

Step-by-step explanation:

a)

The motion of both balls is a free-fall motion: it means that the ball is acted upon the force of gravity only.

Therefore, this means that the motion of the ball is a uniformly accelerated motion, with constant acceleration equal to the acceleration of gravity:

g=32 ft/s^2

in the downward direction.

For the ball dropped from the initial height of h_0 = 98 ft, the height at time t is given by

h(t) = h_0 -\frac{1}{2}gt^2 (1)

The ball which is thrown upward from the ground instead is fired with an initial vertical velocity u_y, and its starting height is zero, so its position at time t is given by

h'(t)=u_y t - \frac{1}{2}gt^2 (2)

Therefore, the polynomial that represents the distance between the two balls is:

h(t)-h'(t)=h_0 - \frac{1}{2}gt^2 - (u_y t - \frac{1}{2}gt^2) = h_0 -u_y t

b)

Now we interpret this polynomial, which is:

\Delta h(t) = h_0 -u_y t

which represents the distance between the two balls at time t.

The interpretation of the two terms is the following:

- The constant term, h_0, is the initial distance between the two balls, at time t=0 (in fact, the first ball is still at the top of the building, while the second ball is on the ground). For this problem, h_0 = 98 ft

- The coefficient of the linear term, u_y, is the initial velocity of the second ball; this terms tells us that the distance between the two balls decreases every second by u_y feet.

5 0
3 years ago
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