A missile is fired at an angle of 75 from the horizontal. At one point, its speed was 900 mph. Find its horizontal velocity in m
1 answer:
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Answer:
b = -3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
6b+14=−7−b
6b+14=−7+−b
6b+14=−b−7
Step 2: Add b to both sides.
6b+14+b=−b−7+b
7b+14=−7
Step 3: Subtract 14 from both sides.
7b+14−14=−7−14
7b=−21
Step 4: Divide both sides by 7.
b= -3