Answer:
a length
Step-by-step explanation:
Answer:
theoretical probability 1/2 or 50%
experimental probability 20/50 or 40%
Answer:
(x + 4)(x - 4)
Step-by-step explanation:
There are actually quite a lot of pairs of binomials the disproves Eric's conclusion, but they all model after the same special product: a^2 - b^2.
The special product a^2 - b^2 can be factored into (a + b)(a - b) and for all real a and b, it will come out as a binomial.
Here is an example:
(x + 4)(x - 4)
We can use the distributive property to get:
x^2 - 4x + 4x - 16
which is the same as
x^2 - 16
This would disprove Eric's conclusion.
Answer:
<u>Secant</u>: a straight line that intersects a circle at two points.
<u>Intersecting Secants Theorem</u>
If two secant segments are drawn to the circle from one exterior point, the product of the measures of one secant segment and its external part is equal to the product of the measures of the other secant segment and its external part.
From inspection of the given diagram:
- M = Exterior point
- MK = secant segment and ML is its external part
- MS = secant segment and MN is its external part
Therefore:
⇒ ML · MK = MN · MS
Given:
- MK = (x + 15) + 6 = x + 21
- ML = 6
- MS = 7 + 11 = 18
- MN = 7
Substituting the given values into the formula and solving for x:
⇒ ML · MK = MN · MS
⇒ 6(x + 21) = 7 · 18
⇒ 6x + 126 = 126
⇒ 6x = 0
⇒ x = 0
Substituting the found value of x into the expression for KL:
⇒ KL = x + 15
⇒ KL = 0 + 15
⇒ KL = 15
Using proportions, considering the weight of each bar and the ratio, it is found that the ship is carrying 52 gold bars.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three.
Each bar weighs 5 kg, and the total weight is of 600 kg, hence the number of bars is given by:
n = 600/5 = 120.
The proportion of gold bars is given by:
p = 13/(13 + 17) = 13/30
Hence, out of 120 bars, the number of gold bars is given by:
nG = 120 x 13/30 = 4 x 13 = 52.
More can be learned about proportions at brainly.com/question/24372153
#SPJ1
