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Eddi Din [679]
3 years ago
8

Which triangle is similar to JKL?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
5 0
So is this just a free answer or?
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Solve the equation 4 (x-3) + 5=1
pishuonlain [190]
If your solving for x, x=2 
6 0
3 years ago
The measure of central angle xyz is radians. What is the area of the shaded sector? 32 85 96 256.
statuscvo [17]

If the measure of central angle is 3π /4 radians, then the area off the shaded sector is 96π square units

The radius of the circle = 16 units

The central angle of the shaded region = 3π /4 radians

The area of the sector = (θ/ 360) × πr^2

Where θ is the central angle of the sector

r is the radius of the sector

Substitute the values in the equation

The area of the sector = ((3π /4) /360) × π × 16^2

Convert the radians to the degrees

= (135/360) × 256π

Multiply the terms

= 96π square units

Hence, the area of the shaded sector is  96π square units

The complete question is

The measure of central angle XYZ is 3 pie / 4 radians. What is the area of the shaded sector?

Learn more about area of the sector here

brainly.com/question/7512468

#SPJ4

5 0
1 year ago
Write an equation in slope-intercept form for a line that passes through the given pair of points. (-6,5), (-9,0)
11111nata11111 [884]
Slope intercept form is y=mx+b  because m=slope and b=y-intercept hence "slope intercept form"...

m=deltay/deltax=(0-5)/(-9--6)=-5/-3=5/3 so far we have now:

y=5x/3 +b, using any point, I'll use (-9,0) we can now solve for b or the y-intercept...

0=-9(5)/3 +b

0=-15+b, so b=15 and our line is:

y=5x/3 + 15 or more neatly

y=(5x+45)/3
4 0
3 years ago
Find an equation of the line passing through each of the following pairs of points. a (−3, 1), (0, 3)
Svetlanka [38]

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{2}{0+3}\implies \cfrac{2}{3}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=\cfrac{2}{3}(x+3) \\\\\\ y-1=\cfrac{2}{3}x+2\implies y=\cfrac{2}{3}x+3

5 0
3 years ago
line y = 2x+1 is transformed by a dialation with a scale factor of two and centered at (0,-4). what is the equation of the image
Gekata [30.6K]

Answer: y = 2x + 6

Step-by-step explanation:

Here the equation of line,

y = 2x + 1

y-intercept of the line is, (0, 1)

And, the slope of the line is 2.

Since, If a point (x,y) is dilated by a scale factor k about a point (a,b),

Then transformed point are get by,

(x,y)\rightarrow (k(x-a)+a, k(y-b)+b)

Thus, The transformed point of point (0,1) when dilation is occur by the scale factor 2 about the point (0,-4),

(0,-4)\rightarrow (2(0-0)+0, 2(1+4)-4)

(0,-4)\rightarrow (0, 6)

Thus, the point of the new line is (0,6)

And, the slope of the new line is 2 ( because in the dilation, the slope of the line does not change)

Thus, the equation of new line,

(y - 6) = 2 (x - 0)

y - 6 = 2x

y = 2x + 6


5 0
3 years ago
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