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Eddi Din [679]
3 years ago
8

Which triangle is similar to JKL?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
5 0
So is this just a free answer or?
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When using the inspection method, which number would you add to (and subtract from) the constant term of the numerator in this e
guajiro [1.7K]
We are looking for k in the equation

(x+4)(x+k/4) = x^2+7x+k

The left hand side expands to:
x^2+(4+k/4)x+k = x^2+7x+k

Comparing coefficients for the linear terms, we have the equation

(4+k/4)=7
Solving for k:
16+k=28
k=12

Thus the number to be subtracted is 15-k=15-12=3
5 0
4 years ago
The formula for finding the perimeter of equilateral triangle is P=3s. how can you transform the formula so that it could be use
Mandarinka [93]

Your answer is D. Hope this helps -John



5 0
3 years ago
How to find the angle of a triangle with 3 sides?
Molodets [167]

Explanation:

The Law of Cosines specifies the relationship between the three sides of a triangle and any one of the angles. If the sides are designated a, b, and c, and the angle opposite side c is C, then it tells you ...

  c² = a² + b² -2ab·cos(C)

This relationship can be used to find any and all angles, given the three sides of a triangle. Or, having found one angle using the Law of Cosines, the others can be found using the Law of Sines:

  sin(A)/a = sin(B)/b = sin(C)/c

_____

Typically, inverse functions are required. That is, from the Law of Cosines, ...

  C = arccos((a² +b² -c²)/(2ab))

And from the Law of Sines, ...

  A = arcsin(a/c·sin(C))

  B = arcsin(b/c·sin(C))

_____

<em>Note on solving triangles</em>

It often works best to make use of exact values where possible. It is also a good idea to start with the longest side/largest angle. Of course, once you have two angles the other can be found as the supplement of their sum.

8 0
3 years ago
How is the process of multiplying different from the process of adding fractions?
Iteru [2.4K]
By multiplying fractions, you aren't changing any of them. For example 1/2 times 1/3 all you do is multiply. But to add 1/2 and 1/3 you would have to get a common denominator.<span />
7 0
4 years ago
What is true about the solution of x^2/2x-6=9/6x-18?
Marizza181 [45]
\text{The domain:}\\2x-6\neq0\ \wedge\ 6x-18\neq0\\D:x\neq3\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{6x-18}\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{3(2x-6)}\\\\\dfrac{x^2}{2x-6}=\dfrac{3}{2x-6}\iff x^2=3\to x=\pm\sqrt3
Answer:
<span>x= +-√3 and they are actual solutions.</span>

6 0
3 years ago
Read 2 more answers
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