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2 years ago

8

Mathematics

1 answer:

yanalaym [24]2 years ago

8 0

ITS Y,X I just took it. I hope this helped you

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The sum of 2 trinomials is 7x^2 - 5x + 4. If one of the trinomials is 3x^2 + 2x - 1, then what is the other trinomial?

Hunter-Best [27]

We can subtract the sum of the two trinomials by one of the trinomials.
(7x²-5x+4)-(3x²+2x-1)
Let's look at each part.
7x²-3x²=4x²
-5x-2x=-7x
4-(-1)=5
So, the trinomial should look like:
4x²-7x+5
So, C. 4x²-7x+5 is the other trinomial.

8 0

3 years ago

Simplify:<br> 3(8) ° . (3) -2

jek_recluse [69]

3 x 8 = 24

3 x -2 = -6

reply if you this was wrong or you needed a different answer pls >:(

3 0

3 years ago

Order the following numbers from least to greatest. √11, -0.4, (-4/3), 0.8, √2

agasfer [191]

Answer:

(-4/3), 0.4, 0.8, √2, √11

Step-by-step explanation:

√11=3.316624790355399849114932736670686683927088545589353597058

0.4

(-4/3) = -1.33333333333333333333333333333333333333333333333333333333

0.8

√2=1.414213562373095048801688724209698078569671875376948073176

Thus :

(-4/3)

0.4

0.8

√2

√11

8 0

3 years ago

Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.

Tasya [4]

Answer:

The answer is " $\bold{\frac{7}{2}}$ "

Step-by-step explanation:

Given value:

$\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0$

Find:

area=?

calculation:

$\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx + \int_{0}^{1} (4x+3x^2-x^3) dx \\\\$

$= -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\= ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\= ( \frac{3}{4}) + (\frac{11}{4})\\\\= \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\$

7 0

2 years ago

POSSIBLE POINTS 125

Lena [83]

Answer:

$51.36

Step-by-step explanation:

48×7%

5 0

2 years ago