we have
y > -2
x + y < 4
using a graph tool
see the attached figure
The shaded area is the solution of the system
<u>Part 1) </u>Name an ordered pair that is a solution to this system and explain how you know that this is a solution point
Let
A ( -40,20)
The point A is solution of the system because the point lie on the shaded area
<u>Check</u>
If the point A is solution of the system must satisfy both system inequalities
point A
x=-40
y=20
substitute
y > -2-------> 20 > -2-------> is ok
x + y < 4----> -40+20 < 4-----> -20 < 4-----> is ok
therefore
<u>the answer Part 1) is</u>
The point A is a solution of the system
Part 2) Name an ordered pair that is not a solution to the system and explain how you know that it is not a solution
Let
B(20,20)
The point B is not solution of the system because the point not lie on the shaded area
<u>Check</u>
If the point B is not solution of the system must not satisfy both system inequalities
point B
x=20
y=20
substitute
y > -2 -------> 20 > -2-------> is ok
x + y < 4---->20+20 < 4-----> 40 < 4------> is not ok
therefore
<u>the answer part 2) is</u>
The point B is not a solution to the system
Answer:
726.572699
Step-by-step explanation:
According to differentials
(x+Δx)³ = x³ + 3x²Δx + 3x(Δx)² + (Δx)³ (Using binomial expansion)
Using this formula to solve (8.99)³, this can also be written as;
(8.99)³ = (9-0.01)³ where
x = 9
Δx = -0.01
Substitute this vales into the differential expression above
(9+(-0.01))³ = 9³ + 3(9)²(-0.01) + 3(9)(-0.01)² + (-0.01)³
(9+(-0.01))³ = 729 + (243)(-0.01) + 27(0.0001) + (-0.000001)
(9+(-0.01))³ = 729-2.43+0.0027-0.000001
(9+(-0.01))³ = 729-2.43+0.0027-0.000001
(9+(-0.01))³ = 726.572699
Hence 8.99³ = 726.572699 (Using differential)
Using calculator;
8.99³ = 726.572699
Answer:
Expressed as a mixed number in its simplest form, 27/4 is equal
to 6 3/4 or six and three quarters.
Step-by-step explanation:
12 inches go into one foot, so we can calculate the volume of the tank in inches to make the calculations that follow easier. Therefore, to calculate the volume of the tank, we use length x breadth x height = 4 x 2 x 2 = 16 square feet x 12 for square inches = 192 square inches.
Every 12 square inches Joseph can fit a one inch fish. The fish that he has are 3 inches long, therefore he can only fit one fish every 36 square inches.
That means that if we take the total volume of the tank and divide it by the space that a 3 inch fish will take up, we are left with 192/36 = 5.3 fish.
You cannot have a third of a fish, so we round off to the nearest whole number, and we determine that Joseph can put 5 fish in his new aquarium.
