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nadya68 [22]
3 years ago
9

How do you solve the equation 0.4(2x+0.5)=3[0.2x+(-2)]-4

Mathematics
2 answers:
dusya [7]3 years ago
6 0
 <span>0.4(2x+0.5)=3[0.2x+(-2)]-4 
</span>
 <span>0.8x+0.2=0.6x-6-4 </span> 
<span>
0.8x-0.6x=-6-4-0.2 
</span>
 <span>0.2x=-10.2 </span> 
<span>
x=-10.2/0.2 
</span>
 <span>x=-51</span>
sergey [27]3 years ago
6 0
0.4(2x+0.5)=3[0.2x+(-2)]-4<span>

</span>0.8x+0.2=0.6x-10

0.2x=-10.2

x= \frac{-10.2}{0.2}

x=-51
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Expression A decays at a rate of 5% every three months, while Expression B grows at a rate of 12% every four months  and  Expression A has an initial value of 624, while expression B has an initial value of 725 , Option B and E are the correct statements.

<h3>What is an Expression ?</h3>

It is a mathematical statement tat consists of variables , constants and mathematical operators.

It is given that

The company's records show the sales of short boards decrease every three months as represented by expression A, where t is the number of years that the boards have been for sale.

The company's records show that the sales of long boards increase every four months as represented by expression B, where t is the number of years that the boards have been for sale.

\rm Expression\; A = 624(0.95)^{4t}\\\\Expression \; B = 725(1.12)^{3t}

From observing both the expression the initial value is when t = 0

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B = 725

and so Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every four months  and  Expression A has an initial value of 624, while expression B has an initial value of 725 , Option B and E are the correct statements.

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