3 years ago

How do you solve the equation 0.4(2x+0.5)=3[0.2x+(-2)]-4

2 answers:

6 0

0.4(2x+0.5)=3[0.2x+(-2)]-4

0.8x+0.2=0.6x-6-4 

0.8x-0.6x=-6-4-0.2

0.2x=-10.2 

x=-10.2/0.2

x=-51

sergey [27]3 years ago

6 0

$0.4(2x+0.5)=3[0.2x+(-2)]-4$ 

 $0.8x+0.2=0.6x-10$

$0.2x=-10.2$

$x= \frac{-10.2}{0.2}$

$x=-51$

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