All categories

3 years ago

How do you solve the equation 0.4(2x+0.5)=3[0.2x+(-2)]-4

2 answers:

6 0

0.4(2x+0.5)=3[0.2x+(-2)]-4

0.8x+0.2=0.6x-6-4 

0.8x-0.6x=-6-4-0.2

0.2x=-10.2 

x=-10.2/0.2

x=-51

sergey [27]3 years ago

6 0

$0.4(2x+0.5)=3[0.2x+(-2)]-4$ 

 $0.8x+0.2=0.6x-10$

$0.2x=-10.2$

$x= \frac{-10.2}{0.2}$

$x=-51$

You might be interested in

Simplify the polynomial 3x5-2x+4-x5+x2

MariettaO [177]

Answer:

-65 is answer if we will solve it then it will be answer

4 0

2 years ago

I don’t understand this one

Masja [62]

Answer:

see below

Step-by-step explanation:

Put -1 where x is in each expression and evaluate it.

You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...

(x +1)

Substituting x=-1 into this factor makes it be ...

(-1 +1) = 0

Evaluating the first expression, we have ...

$\dfrac{4(x+1)}{(4x+5)}=\dfrac{4(-1+1)}{4(-1)+5}=\dfrac{4\cdot 0}{1}=0$

This first expression is one you want to "check."

You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)

5 0

3 years ago

PLS HELPPPP 14. IF m1 = (x + 13)° mz2 = 39° AND mz3 = (5x + 4)º. SOLVE FOR X.

forsale [732]

Answer: x=12

Step-by-step explanation:

$m\angle1=(x+13)^0 \ \ \ \ \ m\angle2=39^0\ \ \ \ m\angle3=(5x+4)^0\\$

The sum of the angles of the triangle is 180°:

$(x+13)+39+(180-(5x+4))=180\\\\x+13+39+180-5x-4=180\\\\-4x+48=0\\\\-4x+48+4x=0+4x\\\\48=4x$

Divide both parts of the equation by 4:

$12=x\\\\Thus,\ x=12$

8 0

1 year ago

line segment with one endpoint at (2,5) is divided in the ratio 4:5 by the point (10,1). which coordinates could represent the o

rodikova [14]

Answer:

(20,-4)

Step-by-step explanation:

We are given;

One end point as (2,5)

Point of division as (10,1)

The ratio of division as 4:5

We are required to calculate the other endpoint.

Assuming the other endpoint is (x,y)

Using the ratio theorem

If the unknown endpoint is the last point on the line segment;

Then;

$\left[\begin{array}{ccc}10\\1\end{array}\right]$ = $\frac{4}{5} \left[\begin{array}{ccc}x\\y\end{array}\right]$ + $\frac{5}{9}\left[\begin{array}{ccc}2\\5\end{array}\right]$