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attashe74 [19]
3 years ago
10

Expanding form for 73,489

Mathematics
2 answers:
taurus [48]3 years ago
8 0

Answer:

70,000+3,000+400+80+9

Step-by-step explanation: hope this help!!

slavikrds [6]3 years ago
4 0
70000
+3000
+400
+80
+9
I like to stack and add plz say this help u
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For the statement? below, write the claim as a mathematical statement. State the null and alternative hypotheses and identify wh
snow_tiger [21]

Answer:

Option E - sigma greater than or equal to $327

Step-by-step explanation:

In this question, we are testing whether the standard deviation of the base price of a certain type of all-terrain vehicle is at least $327.

Now, standard deviation is denoted by the symbol sigma(σ). Since the test is saying it should be at least $327, it means it should either be equal to $327 or greater than $327.

Thus, we would use the symbol ≥ which means "greater than or equal to".

Thus, the claim as a mathematical statement would be;

sigma greater than or equal to $327

5 0
3 years ago
Please help, and plz don't be saying this is the right answer if u dont know for sure.
zepelin [54]

Answer:

135 degrees

Step-by-step explanation:

(8x-7)+(12x+57)=180

combine like terms

20x+50 = 180

subtract 50 on both sides

20x = 130

divide by 20

x = 130/20

x = 13/2

x = 6.5

cpq = 12x+57

cpq = 78 + 57

cpq = 135

4 0
2 years ago
Find the volume of a square pyramid with a base area of 18inch squared and the height of 4 inches
den301095 [7]
Vpyramid=1/3 times area of base times height
volume=1/3 times 18 square inches times 4in
volume=6 square inches times 4in
volume=24 cubic inches


the volume is 24 cubic inches
5 0
2 years ago
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

  • \theta = 240°
  • r = 16 ft

\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
  • r = 10 mi

\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

  • \theta = 60°
  • r = 7 km

\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
Find the slope of the line that passes through (4, 6) and (1, 10).
Jlenok [28]

Answer:

given us,

(x1y1) = (4,6)

(x2y2)= (1,10)

here

slope= (y2-y1)/ (x2-x1)

= (10-6)/ (1-4)

= 4/ (-3)

Step-by-step explanation:

4/ (-3)

5 0
3 years ago
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