Area of EBA = 60
(10 * AB)/2 = 60
AB = 12
Trapezoid Area = (12 + 28) /2 * height
Trapezoid Area = 20 *10
Trapezoid Area = 200 which is D
Answer:
x = 14
Step-by-step explanation:
It's given in the question that a point R lies between the two points Q and S.
Therefore, by addition postulate of segments,
QS = QR + RS
Now we substitute the values of the given segments,
3x - 5 = (35 - x) + (3x - 26)
3x - 5 = -x + 3x + 35 - 26
3x - 5 = 2x + 9
3x - 2x = 5 + 9
x = 14
Therefore, the value of x is 14.
x = longer section
y = shorter section
x + y = 109
x = 2y + 10
so we sub in eq 2 into eq 1
2y + 10 + y = 109
3y + 10 = 109
3y = 109 - 10
3y = 99
y = 99/3
y = 33 <=== shorter section is 33 cm
x = 2y + 10
x = 2(33) + 10
x = 66 + 10
x = 76 <=== longer section is 76 cm
In the scenario above, James can we create a function to combine the two by f ( x ) = 8 x + 118.
<h3>What is the simplification about?</h3>
In the question above, to be able to create a function, we have to show that;
s ( x ) = 102
a ( x ) = 8 ( x + 2 )
So, a function that combines the two will be:
f ( x ) = s ( x ) + a ( x ) = 102 + 8 ( x + 2 ) =
= 102 + 8 x + 16
Therefore f ( x ) = 8 x + 118
Learn more about simplification from
brainly.com/question/723406
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