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Brums [2.3K]
3 years ago
14

The diagram shows a track composed with a semicircle on each end. The area of the rectangle is 8,400 square meters. What is the

perimeter of the th rack? Use 3.14 for pi
Mathematics
1 answer:
MrRa [10]3 years ago
7 0

Answer:

468.4 meters

Step-by-step explanation:

Find the width of the rectangle.

The area of a rectangle is A=length*width. Substitute the values of length and area and solve for width.

A=length*width

8,400=140*width

60= width

Use the width of the rectangle to find the circumference of the semicircles. Since each semicircle is half of a​ circle, the perimeter of the two semicircles is equal to the circumference of one circle.

The circumference of a circle is equal to pi​d, where d is the diameter. The diameter of the semicircle is the same as  the width of the rectangle.

​So, the diameter is 60 meters. Substitute the diameter into the formula for the circumference and simplify using 3.14 for pi.

≈188.4

(2 times 140)+ 188.4

​So, the perimeter of the track is 468.4 meters.

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Answer:

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