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Andru [333]
3 years ago
6

What are potential roots of p(x) = x4 + 22x2 – 16x – 12

Mathematics
2 answers:
kow [346]3 years ago
8 0
Simplify <span>22\times 2<span>22×2</span></span> to <span>44<span>44</span></span>
<span><span>{x}^{4}+44-16x-12<span><span>x<span><span>​4</span><span>​​</span></span></span>+44−16x−12</span></span>Collect like terms
<span><span>{x}^{4}+(44-12)-16x<span><span>x<span><span>​4</span><span>​​</span></span></span>+(44−12)−16x</span></span> Simplify</span><span><span>{x}^{4}+32-16x<span><span>x<span><span>​4</span><span>​​</span></span></span>+32−16x</span></span><span>
</span></span></span>
rjkz [21]3 years ago
4 0

Answer:

±1, ±2, ±3, ±4, ±6 and ±12

Step-by-step explanation:

The potential roots are obtained as following:

potential roots = factors of the constant term / factors of leading coefficient

The constant term is -12, its factors are ±1, ±2, ±3, ±4, ±6 and ±12

The leading coefficient is 1, its factors are  ±1

Therefore the potential roots are ±1, ±2, ±3, ±4, ±6 and ±12

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