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DanielleElmas [232]
3 years ago
13

Calculate the area of a dart which hits the dartboard with a force of 10 N and pressure of 2000 N/cm^2​

Mathematics
1 answer:
STALIN [3.7K]3 years ago
3 0

Answer:

pressure=force/area

2000. ×area =10

area. =10/2000

area =0.005cm²

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Oksana_A [137]

I would say B as the answer... 81 is just to high and 19 doesn't seem right.. so I'm just gonna go with B 23%

I am very sorry if this is wrong in anyway!

7 0
2 years ago
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George wants to purchase a gift for his father for Father’s Day that cost 67.25 if he has already saved 7/8 of the amount how mu
Arlecino [84]

Answer:

$58.84375, rounded ≈ $58.84

Step-by-step explanation:

You can do 67.25 x 7/8 (use a calc if you are lazy) = 58.84375

I'm guessing you don't need to round so I'm going to add both real and rounded answers

3 0
2 years ago
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
Find the distance between the points (13,5) and (10,1)
ElenaW [278]
The distance is (3,4)

Simply subtract the x and y functions.

13 - 10 = 3 

5 - 1 = 4 

8 0
3 years ago
Subtract 3x squared +7x-4 from 8x squared-6+2 your answer should be polynomial in standard form
aleksley [76]

Answer:

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Step-by-step explanation:

8x² - 6x + 2 - (3x² +7x -4)

Simplify the expression:

8x² - 6x + 2 - 3x² -7x + 4

Combine like terms:

5x² - 13x + 6

6 0
3 years ago
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