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3 years ago

Evaluate using the values given. ZX - [z - (4 + x)/6] when x = 2, z = 6

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

5 0

Answer:

Step-by-step explanation:

First, you should replace the variables with the numbers. So,

2(6)-[6-(4+2)/6]

Don't worry, it'll look less confusing later! Next, solve the parentheses that are in the very middle.

2(6)-[6-6/6]

2(6)-[6-1]

12-5

I really hope this helps you!!! Have an amazing day c:

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Which pair of fractions and mixed numbers have a common denominator of 20?

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Answer: The answer is the 4th option

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3 years ago

V= 2i +9j Find ||9v||

Korvikt [17]

Answer:

9 $\sqrt{85}$

Step-by-step explanation:

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3 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

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4 0

2 years ago

31/40 in simplest form

I am Lyosha [343]

Answer:

31/40

Step-by-step explanation:

It cannot be reduced anymore. It is already in simplest form.

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3 years ago