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emmainna [20.7K]
3 years ago
6

Angie bought 312 pounds of apples to make a pie. There are 16 ounces in one pound. How many ounces of apples did she buy?

Mathematics
1 answer:
ruslelena [56]3 years ago
5 0

Answer:4992

Step-by-step explanation:

Multiple 312 by 16

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The sum of two complementary angles is 90°. For one pair of complementary angles, the measure of the first angle is 15 less than
steposvetlana [31]

let 2nd angle = x

 then 1st angle = 2x-15

 then you have 90 = x + 2x-15

2x +x = 3x

 so now 90 = 3x-15

add 15 to each side

105=3x

x = 105/3 = 35

1st angle = 35 degrees

 2nd angle = 2(35) - 15 = 70-15 = 65


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Help me with this math problem i don’t understand it
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Answer:

13meters

Step-by-step explanation:

c^2=a^2+b^2

12^2+5^2=169

find squareroot of 169 which is 13meters

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Write the equation of the line parallel to 9x - 3y = 27 which passes through the point (6,2)
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Answer:

y=3x-16

Step-by-step explanation:

-3y=-9x+27

y=3x-9

slope: 3

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y-2=3x-18

y=3x-16

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Please help! I will mark you as brainliest!
matrenka [14]

Answer:

3.5 hours traveling

2.5 hours stationary

Step-by-step explanation:

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Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

8 0
3 years ago
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