Answer:
E is not a subspace of 
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.
F(x)=2x-3
f(1/2)=2(1/2)-3
f(1/2)= 1-3
f(1/2)= -2
About 6 that’s what I came up with
Answer:
50 < 40 -5 + p
50 < 35 + p
-35 -35 + p
15 < p
p < 15
At least 15 points.
Step-by-step explanation: