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Papessa [141]
3 years ago
8

Round 2577.8 to the nearest tenth

Mathematics
2 answers:
ehidna [41]3 years ago
8 0

Answer:

2578

Step-by-step explanation:

aivan3 [116]3 years ago
7 0

Answer:

2578

Step-by-step explanation:

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For what values of t, if any, is given vector parallel to vector u = (4,-1): (8t, 2t)? and (1,t^2)?
Radda [10]
The vector would have to be a scalar of (4,-1) in order to be parallel to it
so
 4 = 8t   -1 = 2t

t= 4/8 = 1/2
-1=2t
t= -1/2
3 0
4 years ago
GIVING BRAINLIEST PLSSSSS BE A GOD Jennifer is saving money to buy a bike. The bike costs $294. She has $107 saved, and each wee
bezimeni [28]

Answer:11

Step-by-step explanation:

294-107=187

187/17 =11 weeks

Hope this helps :)

6 0
3 years ago
Round 21/2 to a whole number
Stella [2.4K]

Answer by Mikaatkinsbootiful:

\mathrm{Long\:Division}\:\frac{21}{2}:\quad 10\quad \mathrm{Remainder}1\quad \:\\Convert\:to\:mixed\:number:\:Quotient\frac{Remainder}{Divisor}\\\frac{21}{2}=10\frac{1}{2}\\Mixed number: 10\frac{1}{2}

6 0
4 years ago
Read 2 more answers
How to do the problem ​
charle [14.2K]

Answer:

the answer is 10n-13

Step-by-step explanation:

this is a one step problem, all you need to do is add all the like terms together such as n and 9n and since they are both positives they add up to 10n and then with -10 and -3 they would add together to make -13. thats all there is to it, the answer is 10n-13

7 0
3 years ago
Read 2 more answers
Question Progress
andreyandreev [35.5K]

The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

Step-by-step explanation:

The given is,

                  The sum of two numbers is 21

                   The second number is six times the first number

Step:1

          Let, m - First number

                  n - Second number

Step:2

        From given,

                  n - 6m     ( The second number is six times the first number )

        Equation becomes,

                  Sum = m + n

        Where,

                      21 = m + ( 6m )

                       21 = 7m

                       m = 3

        Substitute m value n becomes,

                        n = 6m

                           = (6 × 3)

                      n  = 18

Result:

          The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

                   

5 0
3 years ago
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