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neonofarm [45]
4 years ago
6

How do you express sin x + cos x in terms of sine only?

Mathematics
1 answer:
frez [133]4 years ago
4 0

Answer:

\sin x + \sqrt{1-\sin^2x}

Step-by-step explanation:

Given: sin x + cos x

To change the given trigonometry expression in term of sine only.

Trigonometry identity:-

  • \sin^2x+\cos^2x=1
  • \cos x=\sqrt{1-\sin^2x}

Expression: \sin x+\cos x

We get rid of cos x from expression and write as sine form.

Expression: \sin x + \sqrt{1-\sin^2x}        \because \cos x=\sqrt{1-\sin^2x}

Hence, The final expression is only sine function.

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Please answer this question!! whoever answers correctly will get brainiest!!!
il63 [147K]

Answer:

x

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Step-by-step explanation:

8 0
3 years ago
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Kaleens chemistry textbook weighs 5/6 of a pound
snow_tiger [21]
What do you want help with an equation or something else

4 0
3 years ago
Junnie walked for 2.5 hours at a distance of 3.2miles per hour. Maurice walked for 1.8 hours at a speed of 4.1 miles per hour.
GREYUIT [131]

We are given speed and time for Junnie and Maurice.

We will use speed distance formula here to find the distance covered by Junnie and Maurice.

The formula is given by:

speed= \frac{distance}{time}

distance = speed * time

Distance covered by Junnie:

We are given speed of Junnie as 3.2 miles per hour and time taken by her is 2.5 hours.

Plugging these values to find distance:

Distance = 3.2 * 2.5 = 8 miles

Distance covered by Maurice:

We are given speed of Maurice as 4.1 miles per hour and time taken by her is 1.8 hours.

Plugging these values to find distance:

Distance = 4.1 * 1.8 = 7.38 miles

Distance covered by Maurice is 7.38 miles whereas that covered by Junnie is 8 miles.

(A) So it is clear that Junnie walked farther.

Now let us find how much farther did Junnie walked.

We can find that by finding the difference between the two distances.

Difference = Distance covered by Junnie - distance covered by Maurice

Difference = 8- 7.38 = 0.62

(B) So Junnie walked 0.62 miles farther.

8 0
3 years ago
A point x is 34m due to east of a point Y . The bearing of a flagpole from x and Y are N18°W And N40°E respectively .
Murljashka [212]

Answer:

The distance of flag post from Y is 38.13 m

Step-by-step explanation:

Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.  

Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.  

Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.  

Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,  

\angle AXY=\angle AXF+\angle FXY

\therefore 90 \degree=18\degree+\angle FXY

\angle FXY=72\degree

Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,  

\angle BYX=\angle BYF+\angle FYX

\therefore 90 \degree=40\degree+\angle FYX

\angle FYX=50\degree

Refer attachment 1.  

From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.

∠YFX+∠FYX+∠FXY=180°

∠YFX+50°+72°=180°

∠YFX=58°

Refer attachment 2.  

Now the distance FY can be calculated using sin rule as follows,  

\frac{\sin X}{FY}=\frac{\sin F}{YX}=\frac{\sin Y}{FX}

Substituting the values,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}=\frac{\sin 50}{FX}

Simplifying first two terms,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}

Cross multiplying,

34\times\sin 72=FY\times \sin 58

\dfrac{34\times\sin 72}{\sin 58}=FY

FY=38.13 m

7 0
3 years ago
Solve for the value of z: 14/5 = z/24<br> ____?
natka813 [3]

Answer:

Step-by-step explanation:

Cross multiplying

5z =14*24

5z = 336

Divide by 5

z = 336/5

Or mixed fraction z= 67(1/5)

Decimal z= 67.2

3 0
3 years ago
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