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neonofarm [45]
4 years ago
6

How do you express sin x + cos x in terms of sine only?

Mathematics
1 answer:
frez [133]4 years ago
4 0

Answer:

\sin x + \sqrt{1-\sin^2x}

Step-by-step explanation:

Given: sin x + cos x

To change the given trigonometry expression in term of sine only.

Trigonometry identity:-

  • \sin^2x+\cos^2x=1
  • \cos x=\sqrt{1-\sin^2x}

Expression: \sin x+\cos x

We get rid of cos x from expression and write as sine form.

Expression: \sin x + \sqrt{1-\sin^2x}        \because \cos x=\sqrt{1-\sin^2x}

Hence, The final expression is only sine function.

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Use the linear combination method to solve the system of equations. Explain each step of your solution.
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Answer:

The value of x is - 3  And The value of y = - 2

Step-by-step explanation:

Given equation as :

3 x - 8 y = 7          ......A

x + 2 y = - 7          ......B

<u>Applying Linear combination method :</u>

A linear combination method in which steps are taken to make both equation coefficient as like terms to get the value of variable .

<u>Step 1 </u>

multiply the equation B with 4

I,e 4 × ( x+ 2 y ) = - 7 × 4

or, 4 x + 8 y = - 28       ......C

<u>Step 2</u>

Arrange  equation A and C in column

So , 3 x - 8 y = 7          .

      4 x + 8 y = - 28

<u>Step 3</u>

Add Eq 3 with Eq 1

I.e (   4 x + 8 y ) + (  3 x - 8 y ) = 7 - 28

Or. ( 4 x + 3 x ) + ( 8 y - 8 y ) = - 21

Or,  7 x + 0 = - 21

∴     x =  - \frac{21}{7} = - 3

Put the value of x in eq A ,  to get the value of y

So , 3 × ( - 3 ) - 8 y = 7

Or,  - 9 - 8 y = 7

Or, 8 y = - 9 - 7 = - 16

∴     y =   \frac{- 16}{ 8} = - 2

Hence The value of x is - 3  And The value of y = - 2   Answer

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