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neonofarm [45]
4 years ago
6

How do you express sin x + cos x in terms of sine only?

Mathematics
1 answer:
frez [133]4 years ago
4 0

Answer:

\sin x + \sqrt{1-\sin^2x}

Step-by-step explanation:

Given: sin x + cos x

To change the given trigonometry expression in term of sine only.

Trigonometry identity:-

  • \sin^2x+\cos^2x=1
  • \cos x=\sqrt{1-\sin^2x}

Expression: \sin x+\cos x

We get rid of cos x from expression and write as sine form.

Expression: \sin x + \sqrt{1-\sin^2x}        \because \cos x=\sqrt{1-\sin^2x}

Hence, The final expression is only sine function.

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Murljashka [212]

Answer:

4262

Step-by-step explanation:

2 + 7x^2- 2x^3-8x +7x^4     at x = 5

= 2 + 7*(5)^2 - 2*(5)^3-8*5 +7*(5)^4

=2+175-250-40+4375

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3 years ago
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Answer:

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this answer is not from the internet

go check yourselves

mark me brainliest

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