i dont seem to understamd
X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)
Answer:
x(t) = - 5 + 6t and y(t) = 3 - 9t
Step-by-step explanation:
We have to identify the set of parametric equations over the interval 0 ≤ t ≤ 1 defines the line segment with initial point (-5,3) and terminal point (1,-6).
Now, put t = 0 in the sets of parametric equations in the options so that the x value is - 5 and the y-value is 3.
x(t) = - 5 + t and y(t) = 3 - 6t and
x(t) = - 5 + 6t and y(t) = 3 - 9t
Both of the above sets of equations satisfy this above conditions.
Now, put t = 1 in both the above sets of parametric equations and check where we get x = 1 and y = -6.
So, the only set, x(t) = - 5 + 6t and y(t) = 3 - 9t satisfies this condition.
Therefore, this is the answer. (Answer)
