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3 years ago

198 = -4x + 2(-6x+3)

1 answer:

4 0

198=-4x+2(-6x+3), 198=-4x-12x+6, 198=-16x+6, collect the like terms, 198-6=-16x, 192=-16x, divide both sides by -16, 192/-16=-16x/-16, x=-12

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Select all pairs of numbers that have a least common multiple of 30.

ddd [48]

5 and 6 and 3 and 10, the pairs of numbers that have a least common multiple of 30.

<u>Step-by-step explanation:</u>

Case 1: LCM (3, 6)

Prime factorization of 3: $1 \times 3$

Prime factorization of 6: $2 \times 3$

Using all prime numbers found as often as each occurs most often we take

$2 \times 3=6$

Therefore LCM (3, 6) = 6.

Case 2: LCM (5, 6)

Prime factorization of 5: $1 \times 5$

Prime factorization of 6: $2 \times 3$

Using all prime numbers found as often as each occurs most often we take

$5 \times 2 \times 3=30$

Therefore LCM (5, 6) = 30

Case 3: LCM (3, 10)

Prime factorization of 3: $1 \times 3$

Prime factorization of 10: $2 \times 5$

Using all prime numbers found as often as each occurs most often we take

$5 \times 2 \times 3=30$

Therefore LCM (3, 10) = 30

Case 4: LCM (5, 10)

Prime factorization of 5: $1 \times 5$

Prime factorization of 10: $2 \times 5$

Using all prime numbers found as often as each occurs most often we take

$5 \times 2=10$

Therefore LCM (5, 10) = 10

8 0

3 years ago

What is the derivative of -5

ololo11 [35]

The derivative of constant numbers is zero.

8 0

3 years ago

For f(x)=x^2,sketch the graph of g(x)=f(-5x+10)

DiKsa [7]

The graph of g(x) = f(-5x+10) is given in the figure.

<h3>What is a graph?</h3>

A diagram showing the relation between two variable quantities,each measured along one of a pair of axes at right angles.

It is given that f(x) = x^2

and g(x ) = f(-5x+10)

Now putting the value of f(x) in g(x) we get,

g(x) = f(-5x+10) = (-5x+10)^2

So, g(x) = (-5x+10)^2

now, making the table for g(x),

0 100

1 81

2 0

3 25

4 100

5 225

Hence,the graph of g(x) = f(-5x+10) is given in the figure.

More about graph :

brainly.com/question/11616742

#SPJ1

3 0

1 year ago

There are 3 people at a party. If each person must shake hands with every other person at the party exactly once, how many hands

Dima020 [189]

<h2>Answer:</h2>

The total number of handshakes that would happen between the three people are:

<h2>Step-by-step explanation:</h2>

There are three people at a party.

Let they be denoted by A,B and C.

Now, the total number of handshakes that would occur will be denoted by:

AB, AC and BC

where AB denotes that A and B shake hands.

AC denote that A and C shake hands.

and BC denote that B and C shake hands.

Hence, total number of handshakes are:

5 0

3 years ago

If ΔABC ≅ΔDEF, then what corresponding parts are congruent?

const2013 [10]

The part of the triangles which are congruent according to the description are; segment AB and segment DE.

<h3>Which parts of the triangles are congruent?</h3>

It follows from the task content that the two triangles ABC and DEF have been established as congruent. On this note, it can be established that by the congruence theorem that corresponding sides which are congruent and whose ratios equal to a constant ratio are segments AB and segment DE.