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anygoal [31]
3 years ago
11

Which descriptions from the list below accurately describe the relationship between triangle QRS and triangle TUV check all that

apply

Mathematics
2 answers:
abruzzese [7]3 years ago
6 0

Answer:

Step-by-step explanation:

From the given figure, from ΔQRS and ΔTUV, we have

∠Q=∠T(56°(given))

∠R=∠U(83°(given))

∠S=∠V(41°(given))

Thus, by AAA similarity of triangles, ΔQRS is similar to ΔTUV.

Also, All the three angles made by both triangles are equal, and also they are similar thus they have same shape.

Thus, option C and D are correct.

masha68 [24]3 years ago
3 0

Answer:  C. Same shape

D. Similar

Step-by-step explanation:

In the given picture we have two triangles, ΔQRS and ΔTUV

such that ∠Q=∠T=56°

∠R=∠U=83°

∠S=∠V=41°

So by AAA postulate of similarity, we have

ΔQRS ≈ ΔTUV

Since, similar figure have same shape.

Thus, we can say both triangles have the same shape.

But non of sides of both triangles are congruent, therefore the given triangle is just similar but not congruent.

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julia-pushkina [17]
In a rhombus opposite angles are equal and all 4 add up to 360
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I think the answer you're looking for is 127
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3 years ago
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
blondinia [14]

Answer:

Step-by-step explanation: For part 1, it makes sense that the form is y = m + c. So, it is a simply rearrangement of the equation to start with, in order to make  the subject. This is the graph in slope-intercept form. From here it is easy to see that gradient  = and the y-intercept = 490. The easiest way to draw a straight-line graph, such as this one, is to plot the y-intercept, in this case (0, 490), then plot another point either side of it at a fair distance (for example substitute  = -5 and  = 5 to procure two more sets of co-ordinates). These can be joined up with a straight line to form a section of the graph, which would otherwise extend infinitely either side - use the specified range in the question for x-values, and do not exceed it (clearly here the limit of -values is 0 ≤ x ≤ 735, since neither x nor y can be negative within the context of the question - the upper limit was found by substituting  = 0). In easy terms, the graph of this function represents how the value of the function varies as the value of x varies. Looking back at the question context, this graph specifically represents how many wraps could have been sold at each number of sandwich sales, in order to maintain the same profit of $1470. When the profit is higher, the gradient is not changed (this is defined by the relationship between the $2 and $3 prices, not the overall profit) - instead the -intercept is higher, therefore we have gleaned that the new y-intercept is 531. Clearly I cannot see the third straight line. However the method for finding the equation of a straight line graph is fairly simple:

1. Select two points on the line and write down their coordinates

2. The gradient of the line =

3. Find the change in  (Δ

4. Find the change in  (Δ

5. Divide the result of stage 3 by the result of stage 4

6. This is your gradient

7. Take one of your sets of coordinates, and arrange them in the form , where your  is the gradient you just calculated

8. There is only one variable left, which is  (the y-intercept). Simply solve for this

9. Now generalise the equation, in the form , by inputting your gradient and y-intercept whilst leaving the coordinates as  and

For example if the two points were (1, 9) and (4, 6):

Δ = 6 - 9 = -3

Δ = 4 - 1 = 3

=  = -1

I choose the point (4, 6)

6 = (-1 * 4) + c

6 = c - 4

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Within the context of the question, I imagine the prices of the two lunch specials will be the same in the third month and hence the gradient will still be  - this means steps 1-6 can be omitted. Furthermore if the axes are clearly labelled, you may even be able to just read off the y-intercept and hence dispose with steps 1-8!

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GenaCL600 [577]
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Masteriza [31]

Answer:

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Step-by-step explanation:

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Finger [1]

Answer:

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Step-by-step explanation:

Gemma had 25.75 grams of frosting

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