Rectangle A ~ Rectangle B
The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
If we are talking about whole numbers, the only number in between 1 and 3 is 2 but if we are talking about numbers in general, there are an infinite amount of numbers (for example, 1.1, 1.12, 1.004, and 1.80543285 are all in between 1 and 3).
Hello!
You first cross multiply
4 * 7 = 28
5 * r = 5 * r
r * 5 = 28
Divide both sides by 5
r = 28/5 = 5.6
The answer is 28/5 or 5.6
Hope this helps!
LCM 14 & 24 = 168
then use the highest exponents for the variables
answer = 168x^6y^6z^8
