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fenix001 [56]
3 years ago
13

Find the area and circumference of a circle that has a diameter of 17mm

Mathematics
1 answer:
lara [203]3 years ago
3 0

Answer:

Area A = 72.25$ \pi $ sq. units

Circumference C = 17$ \pi $

Step-by-step explanation:

The diameter, d of the circle is given to be 17mm.

Since, 2r = d, where r is the radius r = $ \frac{17}{2} $ mm.

Area A of the circle is given by $ \pi r^2 $ sq. units.

Therefore, A = $ \pi \times (\frac{17}{2}) ^2 $= 72.25 sq.mm.

Also, Circumference, C = $ 2 \pi r $ units.

Therefore, C = $  2 \times \pi \times \frac{17}{2} $ = 17$ \pi $ units.

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3 years ago
Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%
bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400  at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}

a = $800

The amount of money invested at 6% = a = 800

The amount of money invested at 4 % = 3a = 3(800) = 2400

So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

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3 years ago
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3 years ago
Read 2 more answers
In the diagram of triangle ADC below, EB || DC, AE = 9, ED = 5, and AB = 9.2. What is the length of AC, to the nearest tenth?
dalvyx [7]

Answer:

14.3

Step-by-step explanation:

9/5= 9.2/x (cross multiply)

5 x 9.2= 46

46 ÷ 9 = 5.1

9.2 + 5.1 = 14.3

8 0
3 years ago
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