Pretty sure it is nine. I hope I helped
Answer:
Step-by-step explanation:
Write an equation to find the number of each type of ticket they should sell. Let "x" be # of adult tickets; Let "y" be # of student tickets: Value Equation: 5x+3y=450- b. Graph your equation.y = (-5/3)x+150
c. Use your graph to find two different combinations of tickets sold. I'll leave that to you.
Answer: Choice A
y + 1 = -3(x+2)
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Explanation:
Let's look through the answer choices.
Choices C and D show that the point (2,1) is on the line. But the graph does not show this. So we can rule out choices C and D.
With choice A, the slope is negative and choice B has a positive slope.
The answer must be choice A because the line is going downhill as we move from left to right.
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A common method is to pick two points on the line and compute the slope using the slope formula
m = (y2-y1)/(x2-x1)
Once you know the slope, you would use point slope form
y - y1 = m(x - x1)
Answer:
A. -4 is to the right of -9 on a horizontal number line.
Step-by-step explanation:
The order in a number line is:
-9 , -8 , -7 , -6 , -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9
As shown above, -4 is to the right of -9 on the horizontal number line.
Answer:
not statistically significant at ∝ = 0.05
Step-by-step explanation:
Sample size( n ) = 61
Average for student leader graduates to finish degree ( x') = 4.97 years
std = 1.23
Average for student body = 4.56 years
<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>
H0( null hypothesis ) : u = 4.56
Ha : u ≠ 4.56
using test statistic
test statistic ; t = ( x' - u ) / std√ n
= ( 4.97 - 4.56 ) / 1.23 √ 61
= 2.60
let ∝ = 0.05 , critical value = -2.60 + 2.60
Hence we wont fail to accept H0
This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05