Answer:
f(x) has three real roots and two imaginary roots.
Step-by-step explanation:
Given that three roots of a fifth degree polynomial function f(x) are -2,2 and (4+i).
Now we need to find about which of the given statements describes the number and nature of all roots for this function.
We know that imaginary roots always occur in conjugate pairs.
So if (4+i) is root then (4-i) must also be the root.
So now we have total 4 roots
-2, 2, (4+i) and (4-i).
Degree of the polynomial is 5 so that means 1 root is still remaining. It can't be imaginary as that must be in pairs
So that means 5th root is real.
Hence correct choice is :
f(x) has three real roots and two imaginary roots.
1. 18
2.8
3.-1
<h3>What is expression?</h3>
An expression is a set of terms combined using the operations +, – , x or ,/.
Given:
1. 22 − 1 (4)
=22- 1*4
= 22-4
= 18
2. 2 + 2 (3)
=2+2*3
=2+6
=8
3. 1 − 2
= -1
Learn more about expression here:
brainly.com/question/14083225
#SPJ1
Okay so for 2x-y > 3
Subtract -2 from each side
-y>-2x+3
Divide by -1
And when you divid you gotta switch signs
So it’s y<2x-3
3x-5y less than and equal to 25
Subtract 3
-5y is less than and equal to -3x+25
Then divide by -5
Flip since we divide
Y more than and equal to 3/5x-5
We always flip signs when we divid or multiple
I hope this help
Sorry if I’m wrong