Answer:
The area is approximately 30.69 cm^2.
Step-by-step explanation:
To solve this problem, we first have to recognize that the side of the block is a rectangle with a semicircle missing. This means that to find the area, we must find the area of the rectangle and then subtract the area of the semicircle. Using the respective formulas, we get the following expression for area:
A = (length * width) - (1/2*pi*r^2)
Now, we must plug in the given values shown in the figure. The length is 9 cm, the width is 4.5 cm, and the diameter is 5 cm. However, the formula asks for the radius, which is simply half of the diameter, or 2.5 cm.
A = (9 cm * 4.5 cm) - (1/2 * 3.14 * (2.5 cm)^2)
Next, we should perform the operations indicated inside the parentheses.
A = 40.5 cm^2 - 9.81 cm^2
Finally, we can subtract the two values (this represents taking away the area of the semicircle from the rectangle).
A = 30.69 cm^2
Therefore, the area of the side is approximately 30.69 cm^2.
Hope this helps!
Answer:
협의회는 지난 해 올해
Step-by-step explanation:
업 하고 있는 것 같은 기분 좋은 시간 보내고 왔습니다 그리고 저는 이렇게 잘 지내고 있습니다 저는 너무 힘들고 또 제 자신이 정말 많은 것 같아요
Answer:
x>4
Step-by-step explanation:
x+3>19-3x
x+3x>19-3
4x>16
x>4
Answer:
1.778 times more or 16/9 times more
Step-by-step explanation:
Given:
- Mirror 1: D_1 = 8''
- Mirror 2: D_2 = 6"
Find:
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?
Solution:
- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:
LGP ∝ A
- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:
A ∝ D^2
- Hence, LGP ∝ D^2
- Now compare the two diameters given:
LGP_1 ∝ (D_1)^2
LGP ∝ (D_2)^2
- Take a ratio of both:
LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2
- Plug in the values:
LGP_1/LGP_2 ∝ (8)^2 / (6)^2
- Compute: LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more
Answer:
f(x)
Step-by-step explanation:
the function f(x) crosses the y-axis higher than either of the other functions, therefore it has the largest y-intercept
