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expeople1 [14]
3 years ago
8

A survey found that 3 out of 5 seventh graders have an email account. It there are 315 seventh graders how many would you expect

to have an email account?
Mathematics
1 answer:
professor190 [17]3 years ago
6 0
189 students should have an email account
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Select All Expressions That Represent The Area Of The Large, Outer Rectangle.
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Answer:

A, C, and E are your answers

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I will mark you Brainliest if your response is correct. Also, I'm offering 20 points.
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740 m^2

Step-by-step explanation:

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Multiply 3/sqrt17- sqrt2 by which fraction will produce an equivalent fraction with rational denominator
zzz [600]

Answer:

B.

Step-by-step explanation:

To simplify something that looks like \frac{\text{whatever}}{\sqrt{a}-\sqrt{b}} you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

\sqrt{a}+\sqrt{b}.

If you had  \frac{\text{whatever}}{\sqrt{a}+\sqrt{b}}, then you would multiply top and bottom the conjugate of \sqrt{a}+\sqrt{b} which is \sqrt{a}-\sqrt{b}.

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens.  The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First:  a(a)=a^2

Outer: a(-b)=-ab

Inner:  b(a)=ab

Last:    b(-b)=-b^2

--------------------------Adding.

a^2-b^2

See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of \sqrt{17}-\sqrt{2} is

\sqrt{17}+\sqrt{2}.

This is the thing we are multiplying and top and bottom.

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Which statement regarding the number of solutions for the linear equation shown below is true?
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Answer: There is no solution.

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What does gemdas and pemdas stands for?
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For pemdas

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