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3 years ago

What are the coordinates of the vertex of the parabola described by the equation below?

Mathematics

1 answer:

yanalaym [24]3 years ago

8 0

Quick answer is (3,5)

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1,284 to the nearest 100 place

prisoha [69]

1,300 because 8 is over 5 and it rounds the 100th place ,(which is 2), to become a 3 which makes the answer 1,300.

7 0

3 years ago

Read 2 more answers

PLEASE HELP!

Wittaler [7]

Answer:

See below

Step-by-step explanation:

Use the formulae directly

For a cone, with base radius = r and height = h, here are the related formula

$\textrm{Slant height l} = \sqrt{r^2 + h^2}$ (1)

$\textrm{Lateral surface area} = \pi r l$

$\textrm {Base area} = \pi r^2$

$\textrm { Total Surface Area SA} = \textrm{Base Area + Lateral Area} = \pi r^2 + \pi rl = \pi r(r + l)$ (2)

$\textrm{Volume V = } (1/3) \pi r^2h$ (3)

Therefore directly plugging in the numbers in the above equations:

Note:

l = slant height in cm
SA = total surface area in sqcm
V = Volume in cubic cm

Figure(a)

r = 4, h = 8

$\textrm{l} = \sqrt{4^2 + 8^2} =\sqrt{80} = 8.944 \\\textrm{SA} = 4\pi(4 + 8.944) = 4\pi(12.944) = 162.66\\\textrm{V} = (1/3)\pi(4^2)(8) = 134.04$

Figure(b)

r = 7, h =15

$\textrm{l} = \sqrt{7^2 + 15^2} =\sqrt{274} = 16.55$

$\textrm{SA} = 7\pi(7 + 16.55) = 517.89$

Figure (c)

r = 5, l = 8

$h = \sqrt{l^2 - r^2} = \sqrt{8^2 - 5^2} = \sqrt{39} = 6.245\\SA = \textrm{SA} = 5\pi(5 + 8) = 204.2\\V = (1/3)\pi(5^2)(6.245) = 163.5$

6 0

2 years ago

Solve square root <br> X^2+12x+43=0

AlekseyPX

$x^2+12x+43=0
$

$x= \dfrac{-b+ \sqrt{b^2-4ac} }{2a}, \dfrac{-b- \sqrt{b^2-4ac} }{2a}$

$x= \dfrac{-12+ \sqrt{12^2-4*43} }{2}$ , $\dfrac{-12- \sqrt{12^2-4*43} }{2}$

$x= \dfrac{-12+2 \sqrt{7i} }{2}, \dfrac{-12-2 \sqrt{7i} }{2}$

$x=-6+ \sqrt{7i},-6- \sqrt{7i}$

5 0

3 years ago

Read 2 more answers

hi i need some smart friends that are in grade 10 thats actually smart to help me i feel so embarressed to ask but anyways i act

Delicious77 [7]

334

Step-by-step explanation:

8 0

2 years ago

Y multiplied by 2 1/2

enot [183]

Answer: