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OlgaM077 [116]
2 years ago
13

Solomon has $188.He wants to purchase concert tickets fir himself and 5 friends.Each ticket cost $19.Does he have enough money?

Explain
Mathematics
1 answer:
Temka [501]2 years ago
8 0
he has 188 bucks and 5 friends plus him each cost 19 bucks so divided 19 and 188 equal answer th em divided the answer and 5
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What is 90 divided by 12???? <br> pls help i need to get my grades up
Andrew [12]

Answer:

7.5

Step-by-step explanation:

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5 0
2 years ago
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A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
5 left! Help please! So close to being done! a. 75. b. 66 c. 122 d. 98. thank you
user100 [1]

Answer:

98

Step-by-step explanation:

180- 122 = 58

58 + 24= 82

180- 82= 98

5 0
2 years ago
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What is an hypothesis?
vova2212 [387]

Answer: A hypothesis is like a prediction

Hope it helps

3 0
3 years ago
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Write the equation in standard form for the circle with center (0, 9) passing through (0, 27/2)
sammy [17]

Given

coordinates of center= (0,9)

Circle passes through (0, 27/2)

Find

Equation of circle

Explanation

The equation of circle in standard form is

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-0)^2+(y-9)^2=r^2 \end{gathered}

We know the circle passes through (0,27/2), then

\begin{gathered} (0-0)^2+(\frac{27}{2}-9)^2=r^2 \\ r=4.5 \end{gathered}

So the equation in the standard form is

(x-0)^2+(y-9)^2=4.5^2

Final Answer

(x-0)^2+(y-9)^2=4.5^2
8 0
1 year ago
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