Let's say X is the first brother's age
x+2 is second brother, and x+4 is the third brother
Since the product of the first and third boy x(x+4) is 20 more than twice (20+x(x+2), our equation is x(x+4)=20+2(x+2)
Simplify from there and see what you get.
Answer:
The machine should be set at a mean weight of 51.23 kg.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
At what mean weight should the machine be set so that only 5% of the bags are underweight contain less than 50kg of sand?
We want 50 to be the 5th percentile.
So when X = 50, Z has a pvalue of 0.05. So when X = 50, Z = -1.645. We use this to find the mean weight
The machine should be set at a mean weight of 51.23 kg.
Answer:
16 ounces of clay he need.
Step-by-step explanation:
Given:
Reggie had 2-pound bricks of clay and his job is to give 4 ounces of clay to each student.
There are total 28 students.
Now, to get how much ounces of clay does the each student have first we multiply the number of students to the number of ounces of clay.
Number of students × Number of ounces of clay:
Now, total amount of clay ounces Reggie had= 3×32=96 ounces. (1 pound = 16 ounces, 2 pound = 32 ounces.)
So, the total amount of clay he need is =
=
Therefore, 16 ounces of clay he need.
The slope is rise (number on the y-axis) over run (number on the x-axis); in other words rise/run. Simplify the rise/run if possible.