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Mashcka [7]
4 years ago
13

While driving to the store, your vehicle traveled 30 miles. While you we traveling, your vehicle traveled at an average speed of

15 miles per hour due to traffic. How long did it take you to get to the store? Calculating Time.
Whoever answers correctly gets marked brainliest :)
Mathematics
1 answer:
Olenka [21]4 years ago
7 0

Answer:

2 hours

Step-by-step explanation:

30 miles/x hours = 15 miles/1 hour

30 = 15x

x = 2 hours

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2 years ago
Can you please help me with this problem.
Nimfa-mama [501]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
Can someone please help me with math.
sattari [20]

Answer:

A: strongly positive

Step-by-step explanation:

Hopefully this helps!

6 0
3 years ago
Need help with working perimeter and area please
SVETLANKA909090 [29]

Answer:

Area = 228 m²

Perimeter = 60 m

Step-by-step explanation:

The figure given shows a rectangle that has a cut triangular portion.

✔️Area of the figure = area of rectangle - area of the triangular cut portion

= L*W + ½*bh

Where,

L = 20 m

W = 12 m

b = 20 - (8 + 8) = 4 m

h = 6 m

Plug in the values

Area = 20*12 - ½*4*6

Area = 240 - 12

Area = 228 m²

✔️Perimeter = perimeter of rectangle - base of the triangular cut portion

= 2(L + W) - b

L = 20 m

W = 12 m

b = b = 20 - (8 + 8) = 4 m

Plug in the values

Perimeter = 2(20 + 12) - 4

= 2(32) - 4

= 64 - 4

Perimeter = 60 m

5 0
3 years ago
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