Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
Answer:
Step-by-step explanation:
when (x,y) is rotated through 180 then new coordinates are (-x',-y')
G(6,4)→G'(-6,-4)
Answer:
24 feet in lenght and 15 in width
Step-by-step explanation:
Answer:
f(2)=7
f(-1)=+1
Step-by-step explanation:
f (2)= 2³-2²+3 =8-4+3=7
f (-1)= (-1)³-(-1)²+3= -1- (+1) +3= -1-1+3=+1
Answer:
Cost price=100%
Step-by-step explanation:
