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vodka [1.7K]
3 years ago
6

3^15 is the product of which of the following two

Mathematics
1 answer:
AleksandrR [38]3 years ago
4 0

Answer:

Last option.

Step-by-step explanation:

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Given the points A and BThe coordinates of point A = ( 3 , 1 )The coordinates of point B = (-1 , -1)The midpoint of AB = ([?],[
mr Goodwill [35]

Given the points A and B

The coordinates of point A = ( 3 , 1 )

The coordinates of point B = (-1 , -1)

The midpoint of AB, is the point C

C will be calculated as following :

C=\frac{A+B}{2}=\frac{(3,1)+(-1,-1)}{2}=\frac{(3-1,1-1)}{2}=\frac{(2,0)}{2}=(1,0)

so, the midpoint of AB = (1 , 0 )

3 0
1 year ago
Drag the tiles to the correct boxes to complete the palrs.
Brut [27]

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

f(x) = 2x + 3

g(x) = x - 1

(f+g)(2)

(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2

At x = 2

(f+g)(2) = 3(2) - 2 = 6 - 2 = 4

Then

(f+g)(2)  = 4

(f-g)(4)

(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4

At x = 4

(f-g)(4) = 4 + 4 = 8

Then

(f-g)(4) = 8

(f ÷g)(2)

(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}

At x = 2

(f \div g)(2) = \frac{7}{1} = 7

Then

(f ÷g)(2) = 7

(f x g)(1)

(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3

Then

(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0

So

(f x g)(1) = 0

4 0
3 years ago
Proving the Converse of the Parallelogram Side Theorem
butalik [34]

Answer:

statement

the sum of two adjacent angle of a triangle is 180° . prove that sides are parallel.

7 0
3 years ago
Solve 4x+5y=13 for y
barxatty [35]

the answers is y equals 8x

4 0
3 years ago
Read 2 more answers
The probability all of the students in this class will be present and on time is 3/10. The probability all of the students are p
cestrela7 [59]

Answer:

3/4

Step-by-step explanation:

A: students present
B: students on time

P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5

P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present

So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5

7 0
2 years ago
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