Question

Find three consecutive even integers such that 4 times the third integer is 4 more than the 3 times the first integer plus two times the second integer.

Answer 1

Let lowest integer be n  then

4(n + 4)  = 3n + 2(n + 2) + 4

4n + 16 = 5n + 8
8 = n  

so three integers are 8,10 and 12.