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Elenna [48]
2 years ago
7

A coin is tossed 450 times and lands on heads 268 times.

Mathematics
2 answers:
alexandr1967 [171]2 years ago
7 0

Answer:

The answer is 182 times.

Step-by-step explanation:

If a coin is tossed 450 times & has already landed on heads 268 times then the remaining times the possibility it will land on tails is 182.

450-268=182

Lerok [7]2 years ago
4 0

Answer:

The answer is 40.44%

Step-by-step explanation:

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What is 5000 rounded to the nearest hundred
Vlada [557]

The next larger hundred is  5,100 .
The next smaller hundred is  4,900 .
5,000  is exactly midway between  4,900  and  5,100.
Neither of them is closer to  5,000  than the other one is.
So  5,000  is already rounded to the nearest hundred.

4 0
3 years ago
Read 2 more answers
1/3 + a + 5/4. what is A
USPshnik [31]

Answer:

a = -1.58

Step-by-step explanation:

1/3 +a+5/4 =0

1/3+5/4= -a

4+15/12 = -a

19/12 = -a

1.58= -a

1.58/-1 = -a/-1

-1.58 = a

6 0
3 years ago
20)
Nataly [62]

Answer:

babysitting = $9

working at coffeehouse = $12

x = hours for babysitting

y = hours at coffeehouse

minimum = ≥

9x + 12y ≥ 240

Step-by-step explanation:

just a short note on which symbol you should use when you see these words in inequality questions:

i) use ≥

-more than or equal to

-not less than

-at least

-minimum

ii) use >

-more than

-greater than

iii) use ≤

-less than or equal to

-not more than

-at most

-maximum

iv) use <

-less than

7 0
2 years ago
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.5 parts
DochEvi [55]

Answer:

We accept  H₀   with the information we have, we can say level of ozone is under the major limit

Step-by-step explanation:

Normal Distribution

population mean  =   μ₀   =  7.5   ppm

Sample size     n   =  16      df  =  n  -  1  df  =  15

Sample mean      =    μ   =  7.8  ppm

Sample standard deviation   =  s  =  0.8

We want to find out if ozono level, is above normal level that is bigger than 7.5

1.- Hypothesis Test

null hypothesis                          H₀         μ₀   =  7.5

alternative hypothesis             Hₐ          μ₀  >  7.5  

2.-Significance level    α  =  0.01   we will develop one tail-test (right)

then   for   df  =  15    and    α =  0,01   from t -student table we get

t(c)  = 2.624

3.-Compute  t(s)

t(s)  =  (  μ -  μ₀ ) / s /√n            ⇒   t(s)  = ( 7.8  -  7.5 )*4/0.8

t(s)  = 0.3*4/0.8

t(s)  = 1.5

4.-Compare   t(s)   and  t(c)

t(s)  <  t(c)       1.5  <  2.64

Then  t(s) is inside the acceptance region. We accept  H₀

7 0
3 years ago
Help me pls thanks!!!!!!!​
ipn [44]

Answer:

7.   0.37

Decimal value is  - HUNDREDTHS

Fraction value is - \frac{37}{100}

    1.735

Decimal value is  -  TENTHS

Fraction value is - \frac{1735}{1000}

8.   6.075

Decimal value is  - HUNDREDTHS

Fraction value is - \frac{6075}{1000}

      27.05

Decimal value is  - ONES

Fraction value is -  \frac{2705}{100}

9.    0.127

Decimal value is  - THOUSANDTHS

Fraction value is - \frac{127}{1000}

    3.007

Decimal value is  - THOUSANDTHS

Fraction value is - \frac{3007}{1000}

 

4 0
2 years ago
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