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Nostrana [21]
3 years ago
5

On paper, make a rectangle that has points A and B as two of its vertices and has a perimeter of 40 units. Draw and label the tw

o other vertices as points C and D on the coordinate plane. Draw line segments to show the rectangle. What are the coordinates for points C and D.
Mathematics
1 answer:
Westkost [7]3 years ago
8 0

Answer:

A(x,y),B(x+10,y),C(x+10,y-10) \:and\: D(x,y-10)

Step-by-step explanation:

If a Rectangle has a perimeter of 40 units, then we can write that formula and find the a formula for the coordinates:

\left\{\begin{matrix}w+l=20 & \\ w*l=100 & \end{matrix}\right.\Rightarrow w=20-l\Rightarrow (20-l)l=100\Rightarrow -l^2+20l-100=0\Rightarrow l^2-20l+100\Rightarrow (l-10)(l-10)\Rightarrow l=10\therefore l=10\: and\: w=10

Therefore we can say:

A(x,y),B(x+10,y),C(x+10,y-10) \:and\: D(x,y-10)

Technically when w=lin this rectangle is a square, a degenerate square.

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Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are . If point D
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Given:
A has coordinates (-6,5)
C has coordinates (3.6,-0.4).
C divides AB in the ratio 3:2.

Refer to the diagram shown below.
The coordinates of B are determined by
\frac{3.6-(-6)}{x-(-6)} = \frac{3}{3+2} \\ \frac{9.6}{x+6} = \frac{3}{5} \\ 3(x+6) = 48 \\ 3x +18=48 \\ x=30/3=10
Also,
\frac{5-(-0.4)}{5-y} = \frac{3}{5} \\ 3(5-y) = 27 \\ 15-3y=27 \\ y= \frac{12}{-3} =-4

Answer:
The coordinates of B are (10,-4).

Now, we know the coordinates of line segment AB as A (-6, 5) and B (10,-4).
D (x,y) divides AB in the ratio 4:5.
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\frac{x-(-6)}{10-(-6)} = \frac{4}{4+5} \\ \frac{x+6}{16} = \frac{4}{9} \\ 9(x+6)=64 \\ 9x+54=64 \\ x=1.11
Also,
\frac{5-y}{5-(-4)} = \frac{4}{9}  \\ 5-y = 4 \\ y = 1

Answer:
The coordinates of D are (1.11, 1)

4 0
4 years ago
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Answer:

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