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Serjik [45]
3 years ago
11

Could i please get some help to Evaluate -a- (−8)+b where a =2 and b = -7

Mathematics
2 answers:
gregori [183]3 years ago
8 0
Hello. 

Plug in the variables. 

-2 - (-8) + -7 = - 1

You're welcome. 


Igoryamba3 years ago
3 0
Answer: -1

Explanation:
-a - (-8) + b 
-a + 8 + b (because the - - signs cancel out)
-(2) + 8 + (-7) 
-2 + 8 - 7 = -1
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The interval (-1, 1) is best described as
Bad White [126]

Answer: There's an increasing interval between -1 and 1

While x goes from -1 to 1, the value of y increases (from -2 to 2).

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2 years ago
Spotlight Dance increased the number of dancers on its competition team. Last
Nana76 [90]

Answer:

80%

Step-by-step explanation:

To find percentage increase, we use the following formula:

Percentage Increase = \frac{New-Old}{Old}*100

Here

New means the latest value (which is 18 dancers)

Old means the previous value (which is 10 dancers)

The Multiplication by 100 is to convert the decimal answer to percentage.

So, we have:

New = 18

Old = 10

Now we substitute and find:

\frac{New-Old}{Old}*100\\\frac{18-10}{10}*100\\\frac{8}{10}*100\\80

So, there was an increase of 80%

3 0
3 years ago
What are the next letters BE GL LO QT
Tpy6a [65]
What are we supposed to be basing this off of? is there no additional information?
8 0
3 years ago
A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w
melamori03 [73]

Answer:

The hypothesis is:

<em>H₀</em>: p_{X}-p_{Y}=0.

<em>Hₐ</em>: p_{X}-p_{Y}.

Step-by-step explanation:

Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.

The information provided is:

n_{X}=150\\X=88\\n_{Y}=200\\Y=130

Compute the sample proportion of men and women who exercise regularly as follows:

\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587

\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and \hat p_{X}=0.587.

The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and \hat p_{Y}=0.65.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\hat p=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e. p_{X}-p_{Y}=0.

<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e. p_{X}-p_{Y}.

6 0
3 years ago
Read 2 more answers
What is the median of the data?<br>30,29,16,11,16,20,21,12,13,15,15,23,30​
tia_tia [17]

Answer:

16

Step-by-step explanation:

ascending order:11,12,13,15,15,16,16,20,21,23,29,30,30

number of terms =13

median=[(n+1)/2] th term

=[(13+1)/2] th term

=[14/2] th tem

=7th term

=16

7 0
3 years ago
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