(5,4)
On a system of 2 perpendicular axis with O as origine, the pair (5,4) means:
5 is the distance from the origin O and situated on x-axis (on the right of O)
4 is the distance from the origin O and situated on y-axis (above O)
Then the pair (5,4) is situated in the 1st Quadrant
Your answer would be C. 27/190.
This is because the probability of choosing green as the first marble would be 9/20, as there are 20 marbles in total and 9 of those are green.
The probability of choosing a red marble as the second marble would be 6/19, as no red marbles would have been lost if green was picked first, but there would be one less marble in total.
The 'and' rule for probability, the one that is used to determine the probability of P(A) and P(B), is to multiply, so we need to do 9/20 × 6/19 = 54/380 = 27/190.
I hope this helps!
Hey There
According to me,
no 1 is
SQUARE
no. 2 is
CONGRUENT
HOPE THIS HELPS
X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Answer:
Linda: 3 ; Laura: 15
Step-by-step explanation:
Note that Linda + Laura's age is 18, and that Linda is 12 years younger than her sister.
Let "Linda" = x , "Laura" = y:
x + y = 18
x = y - 12
First, plug in y - 12 for x in the first equation:
(y - 12) + y = 18
Simplify.
2y - 12 = 18
Isolate the variable (y). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First add, then divide.
2y - 12 (+12) = 18 (+12)
2y = 18 + 12
2y = 30
(2y)/2 = (30)/2
y = 30/2
y = 15
Next, plug in 15 for y in the second equation (the other equation would work too).
x = y - 12
x = (15) - 12
x = 3
Linda's age is 3, Laura's age is 15.
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