Ask question

Ask question

All categories

3 years ago

12

Write the equation of the line that passes through (–1, 5) and has a slope of 3 in point-slope form.

1 answer:

LekaFEV [45]3 years ago

6 0

using the formula

$y - y1 = m(x - x1)$

where m is the slope or gradient

from the question, x1 = -1 and y1 =5

and gradient/slope m = 3

substituting them in the formula

$y - 5 = 3(x - ( - 1))$

$y - 5 = 3(x + 1)$

$y - 5 = 3 x + 3$

You might be interested in

What is the slope of the line that passes through the points (10, 3) and (2, 3) ?

Margarita [4]

Slope: (y2-y1)/(x2-x1)
(3-3)/(2-10) = 0/-8 = 0
The slope is 0

3 0

2 years ago

Read 2 more answers

Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an

Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as $V=g(x)$ , where $g(x)=x(6-2x)(8-2x)$ and $0\le x\le3$ .

Expand the function to obtain:

$g(x)=4x^3-28x^2+48x$

Differentiate wrt x to obtain:

$g'(x)=12x^2-56x+48$

To find the point where the maximum value occurs, we solve

$g'(x)=0$

$\implies 12x^2-56x+48=0$

$\implies x=1.13,x=3.54$

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

$g''(x)=24x-56$ , $g''(1.13)=24(1.13)-56=-28.88\:$

This means the maximum volume occurs at $x=1.13$ .

Substitute $x=1.13$ into $g(x)=x(6-2x)(8-2x)$ to get the maximum volume.

$g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26$

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

6 0

3 years ago

The answer for this math problem because I don’t really understand it

andreyandreev [35.5K]

Answer:

See below

Step-by-step explanation:

Start by subtracting 5.2 from both sides of the equation

so "subtraction property of equality " I suppose ......

then the next step would be divide both sides by 2.5

which would be division property of equality

3 0

2 years ago

Read 2 more answers

If angle 0 is in quadrant I, what is the value of

Brilliant_brown [7]

Answer:

$the \: answer \: is \: c \: = - \frac{ \sqrt{14} }{5}$

Step-by-step explanation:

$\sin^{2}0 + ( \frac{ \sqrt{11} }{5} ) ^{2} = 1( \sin^{2}0 + \cos^{2} 0 = 1)$

${ \sin }^{2}0 + \frac{11}{25} = 1 \\ { \sin }^{2}0 = \frac{14}{25}$

$\sin0_{1} = - \frac{ \sqrt{14}}{5} while \sin0_{2} = \frac{ \sqrt{14} }{5}$

Therfore theta is QI
Therfore sin theta >0
$therefore \: \sin0 = \frac{ \sqrt{14} }{5}$

4 0

1 year ago

WORTH 25 POINTS PLEASE HELP!!!

GalinKa [24]

Just subtract the smaller volume from the larger:

10 × 10 ×15 - 7 × 9 × 12

First you would multiply 10 × 10 × 15 = 1500 and then multiply 7 × 9 × 12 = 756.

After you would subtract 1500 - 756 which would give you 744

I hope that helped!

7 0

3 years ago

Read 2 more answers