Answer:
(a) k = C + 273.15, F = 1.8(k - 273.15) + 32
(b) k = 296.15
(c) 25 celcius is greater than 300 kelvis.
Step-by-step explanation:
(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.
C = k - 273.15
C + 273.15 = k
k = C + 273.15
F = 1.8(k - 273.15) + 32
(b) for this one you have to substitute in the previous equation and solve for k.
23 = k - 273.15
k = 23 + 273.15
k = 296.15
(c) you have to convert either kelvins to celcius or celcius to kelvins.
C = k - 273.15
C = 300 - 273.15
C = 26.85
So 25 celcius is greater than 300 kelvis.
Where’s the cone? Is there a picture of a cone? I can’t really solve this, I’m sorry if I bother you
Answer:
A: a^3
B: c^1 or just c
Step-by-step explanation:
Subtract the exponents
Step-by-step explanation:
according to BODMAS
5×5^2÷5-6
5^2=25
5×25÷5-6
5×5-6
25-6=19