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Leona [35]
3 years ago
10

The difference of sample means of two populations is 55.4, and the standard deviation of the difference of sample means is 28.1.

Which statement is true if we are testing the null hypothesis at the 95% confidence level? Medals 0
Answer Choices:

The difference of the two means is significant, so the null hypothesis must be rejected.

The difference of the two means is significant, so the null hypothesis must be accepted.

The difference of the two means is not significant, so the null hypothesis must be rejected.

The difference of the two means is not significant, so the null hypothesis must be accepted.
Mathematics
2 answers:
Anna [14]3 years ago
4 0

Answer:

The difference of the two means is not significant, so the null hypothesis must be rejected.


SVEN [57.7K]3 years ago
3 0

A.  <u><em>The difference of the two means is significant, so the null hypothesis must be rejected.</em></u><em> </em>

B.  <u><em>The difference of the two means is significant, so the null hypothesis must be accepted.</em></u><em> </em>

C.  THE DIFFERENCE OF THE TWO MEANS IS NOT SIGNIFICANT, SO THE NULL HYPOTHESIS MUST BE REJECTED.

D.  <u><em>The difference of the two means is not significant, so the null hypothesis must be accepted.</em></u>


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Can you show all steps to simplify (3x-4)+(x+3)^2
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<span>(3x-4)+(x+3)^2
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= x^2 + 9x  + 5 ..........(combine like terms and simplify)

hope that  helps</span>
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3 years ago
Consider the table of the powers of 8.
garri49 [273]
C loser that’s the correct number
8 0
2 years ago
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Tatiana [17]

Answer:last one

Step-by-step explanation:

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3 years ago
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joe has a piggy bank with $8.90 split upon nickels, dimes, and quarters. The piggy bank contains 76 coins in all. The number of
kozerog [31]

Answer:

There are 38 dimes, 22 nickels and 16 quarters.

Step-by-step explanation:

Let n, d and q represent the # of nickels, dimes and quarters respectively.

Then n + d + q = 76

The value of a nickel is $0.05; that of a dime is $0.10, and that of a quarter is $0.25.

Thus, the value of n nickels is $0.05n (and so on).

The total value of the coins is $0.05n + $0.10d + $0.25q = $8.90.

d = n + q allows us to eliminate d.

First, n + d + q = 76 becomes n + (n + q) + q = 76, and second:

$0.05n + $0.10(n + q) + $0.25q = $8.90.  Here we have succeeded in eliminating d from two different equations, and now we have these two different equations in two unknowns (n and q), which is solvable.

Simplifying both equations, we get:

2n + 2q = 76 and

5n + 10n + 10q + 25q = 890, or 15n + 35q = 890

Let's use the substitution method of solving linear equations:

Rewrite 2n  + 2q = 76 as n + q = 38, or n = 38 - q.  Substituting this result into the second equation, we get:

15(38 - q) + 35 q = 890, or

  570 - 15q + 35q = 890, or

   570 + 20 q = 890.  Then 20q = 890 - 570 = 320, and q = 320/20 = 16.

There are 16 quarters.  Thus, the number of nickels is n = 38 - 16 = 22.

Finally, since n + d + q = 76, 22 + d + 16 = 76, or:

22 + d = 60, or d = 60 - 22 = 38.

There are 38 dimes, 22 nickels and 16 quarters.

4 0
3 years ago
Which of the following is a solution to the equation y = 3x - 1 ?
Korvikt [17]
One way of determining the answer is by substituting the values to the equation. It is done as follows:

A. (4,1)
<span>y = 3x - 1
</span>1 = 3(4) - 1 = 11 -------> not equal

B. (2,5)
<span>y = 3x - 1
</span>5 = 3(2) - 1 = 5 --------> equal

C. (4,3)
<span>y = 3x - 1
</span>3 = 3(4) -1 --------------> not equal

D. (0, -3)
<span>y = 3x - 1
-3 = 3(0) -1 = -1 ---------> not equal</span>
8 0
3 years ago
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