50%. students (in percent) who passed the second exam also passed the first exam.
Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.
Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.
Thus, both tests were passed by 40 of the 80 pupils who passed the second one:
40/80 = 1/2 = 50%.
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Answer:
See explanation
Step-by-step explanation:
Plot the solution sets to both inequalities.
1. For the inequality
First, plot the dotted line
(dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

so the origin does not belong to the needed part. Shade the part, which does not include origin.
2. For the inequality
First, plot the dotted line
(dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

so the origin does not belong to the needed part. Shade the part, which does not include origin.
3. Find the common region of these two shaded parts - this is the solution to the system of two inequalities.
Just graph the coordinates
this picture is the different quadrants on the graph, whichever quadrant the coordinate is in, is what you put in the 2nd column
for example: (-2,-3) is in the 3rd quadrant
if its not in a quadrant its either on x or y axis, so its just on the line, and i assume you know which axis is which
for number 4. You just do subtraction, and then if its negative, it becomes positive since its asking for the absolute value
for example: |-24-11| > |-35| > 35
The discriminant of the equation

is 76.
I hope that helps.
Answer:
x = 0
Step-by-step explanation:
5^0 is 1, meaning that x must equal to 0 for the answer to be 5^0.