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Nezavi [6.7K]
3 years ago
12

If f(t)=3t^2+11 find f(7)

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0

Answer:

f(7) = 158

Step-by-step explanation:

To evaluate f(7) substitute t = 7 into f(t)

f(7) = 3(7)² + 11 = (3 × 49) + 11 = 147 + 11 = 158

Nady [450]3 years ago
6 0

Answer: f(7) = 158

Step-by-step explanation:

f(t)=3t^2+11 find f(7)...... this can be gotten by inputting the function of 't' into the given equation i.e.

f(t) = f(7)

t = 7, so therefore

f(7) = 3t² + 11

f(t) = 3(7)² + 11

    = 3(49) + 11

    = 147 + 11

f(7) = 158

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Citrus2011 [14]

Answer:

C:108+4x+4=180

Step-by-step explanation:

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3 0
3 years ago
(07.03 LC) The steps below show the incomplete solution to find the value of q for the equation 4q − 2q − 4 = −1 + 21: Step 1: 4
Elza [17]

Answer:

3: 2q − 4 = 20

Step-by-step explanation:

Solve for q:

2 q - 4 = 20

Add 4 to both sides:

2 q + (4 - 4) = 4 + 20

4 - 4 = 0:

2 q = 20 + 4

20 + 4 = 24:

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Divide both sides of 2 q = 24 by 2:

(2 q)/2 = 24/2

2/2 = 1:

q = 24/2

The gcd of 24 and 2 is 2, so 24/2 = (2×12)/(2×1) = 2/2×12 = 12:

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8 0
3 years ago
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harina [27]

Answer:

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  • icosahedron: quadrilateral or pentagon

Step-by-step explanation:

<u>Hexahedron</u>

A hexahedron has 6 faces. A <em>regular</em> hexahedron is a cube. 3 square faces meet at each vertex.

If the hexahedron is not regular, depending on how those faces are arranged, a slice near a vertex may intersect 3, 4, or 5 faces. The first attachment shows 3- and 4-edges meeting at a vertex. If those two vertices were merged, then there would be 5 edges meeting at the vertex of the resulting pentagonal pyramid.

A slice near a vertex may create a triangle, quadrilateral, or pentagon.

<u>Icosahedron</u>

An icosahedron has 20 faces. The faces of a <em>regular</em> icosahedron are all equilateral triangles. 5 triangles meet at each vertex.

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3 years ago
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Answer:

30 yrs

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