Answer:
(0, 1).
Method 1 (Substitution):
Substituting our two y's, we get the following:
Thus, the only set of solutions is (0, 1). A quick sketch (either by hand or on Desmos) can confirm this.
Method 2 (Elimination):
We have two equations. We'll let the top one be equation 1 and the bottom one be equation 2. Eliminating as many variables as we can, we subtract (2) from (1) to get:
0 = 3x => x = 0.
So the only set of solutions is (0, 1).
Method 3 (Gaussian elimination):
We can place this in an augmented matrix and row reduce.
![\left[\begin{array}{cccc}1&5&1 & 1\\1&2&1 & 1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%261%20%26%201%5C%5C1%262%261%20%26%201%5Cend%7Barray%7D%5Cright%5D)
Row reducing this gives us:
![\left[\begin{array}{cccc}1&5&1 & 1\\0&3&0 & 0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%261%20%26%201%5C%5C0%263%260%20%26%200%5Cend%7Barray%7D%5Cright%5D)
This tells us that the only solution for x is x = 0 (since we read this as "3x = 0") and thus, the only solution we get is (0, 1).
Answer:
width=6cm, lenth is 7cm
Step-by-step explanation:
Let width of rectangle be x cm
Twice width=2x cm
length=2x-5 cm
Area of the rectangle= L× W =42cm²
(2x-5) × x =42
x(2x-5)=42
2x²-5x-42=0
solving the quadratic equation
x=6cm
width=6cm
length= (2×6)- 5 =7cm
its either a half or part of what its worth
Answer:
a) -2 and 4
b) function 2
Step-by-step explanation:
a)
rate of change is rise over run: change in y / change in x.
function 1:
- i will use first 2 pairs of data
- change in y: 5 - 3 = 2
- change in x: -2 - (-1) = -1
-rate of change = 2/-1 = -2
function 2:
- same idea, but find two points on the graph!
- (0,4) and (-1,0) for example! pick easy points
- change in y is 4. chabge in x is 1
- rate of change is 4
b)
function b has greatest rate of change. 4 > -2
I believe it is 5 but i may need someone to double check <span />
