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Snezhnost [94]
3 years ago
8

Can someone plz help I put the picture

Mathematics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

personally i think x=6

Step-by-step explanation:

but heres how i got it cross multiiply 7.5/4 and x/3.2

witch makes 24=4x then divide by 4 and you get x=6

so.... yeah i think x=6

if brainiest is earned its greatly appreciated

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I need help ASAP! I will give your answer the brainiest answer
Korvikt [17]

This graph will start at (.5, 0) as the vertex.

To find this, all you need to do if find the point where inside the absolute value sign is equal to 0. Since the graph can never have a negative value, this will be the lowest point.

2x - 1 = 0

2x = 1

x = .5

From there, you can plot each point by going up two and to the left one.

Examples of Points: (1.5, 2) and (2.5, 4)

You can also plot the other side of the graph by going up two and to the right one.

These points can be found using the slope, which is the number attached to x (2).

Example of Points (-.5, 2) and (-1.5, 4).


8 0
3 years ago
Solve and make a table ( you may decide what the topic is and the value is.Algebra I)
ratelena [41]

Answer:

Hello...

I'm new user here.

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6 0
3 years ago
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Which inequality represents the graph below s 75
telo118 [61]

Answer:

Top Left

Step-by-step explanation:

Shaded circle means it will be Greater than or equal to or Less then or equal to. The answwers are less that or equal to 75 so s is less than or equal to 75

5 0
3 years ago
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Is 8π rational or irrational number?
evablogger [386]
Irrational i assume
3 0
3 years ago
Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

5 0
3 years ago
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