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PilotLPTM [1.2K]
3 years ago
10

Write an exponential equation in the form y = ab* whose graph passes through points (2, 18) and (5, 60.75).

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0

Let y=ab^x, as described in the problem statement. Plugging in x=2 and x=5 gives us the equations 18=ab^2 and 60.75=ab^5. Since a,b are nonzero, we divide the second equation by the first to get \frac{27}{8}=b^3, which means that b=\frac{3}{2}, after taking the cube root. Plugging this value for b into the first equation, we now have 18=a(3/2)^2=\frac{9a}{4}. Solving gives a=8, and our desired exponential equation is \boxed{y=8\left(\frac{3}{2}\right)^x}.

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Answer:

2 molecule of hydrogen+oxygen=water

5 0
3 years ago
Add and subtract the rational expressions. 7x+5/x-1 -(8x1/x-1+2x-4/x-1) Which statements are true about the process for adding a
anzhelika [568]

Answer:

2. The denominator of the fully simplified expression will be x – 1.

4. The numerator of the fully simplified expression will be –3x + 10.

Step-by-step explanation:

Given the rational expression

\dfrac{7x+5}{x-1} -(\dfrac{8x-1}{x-1} +\dfrac{2x-4}{x-1} )

Let us first simplify before making our deductions.

Opening the brackets

\dfrac{7x+5}{x-1} -(\dfrac{8x-1}{x-1} +\dfrac{2x-4}{x-1} )=\dfrac{7x+5}{x-1} -\dfrac{8x-1}{x-1} -\dfrac{2x-4}{x-1}

Taking LCM

=\dfrac{7x+5-(8x-1)-(2x-4)}{x-1}

Opening the brackets and simplifying

=\dfrac{7x+5-8x+1-2x+4}{x-1}\\\text{Collecting like terms in the numerator}\\=\dfrac{7x-8x-2x+5+1+4}{x-1}\\=\dfrac{-3x+10}{x-1}

The following statements are therefore true:

2. The denominator of the fully simplified expression will be x – 1.

4. The numerator of the fully simplified expression will be –3x + 10.

5 0
3 years ago
I need help asap with this iready lesson!!!!
Ksju [112]

Answer:

top left

Step-by-step explanation:

8 0
3 years ago
-5x + 10x +3 =5x + 6 how many solutions does it have
solong [7]

For this case we must solve the following linear equation:

-5x + 10x + 3 = 5x + 6

Adding similar terms from the left side of the equation:

5x + 3 = 5x + 6

Subtracting5x from both sides of the equation we have:

3 = 6

Thus, equality is not fulfilled. So the equation has no solution.

Answer:

No solution

3 0
3 years ago
What are the solutions of this quadratic equation?
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BMmMakakakakamkaksdkdkdkfjdnhehyuehehejehehheheyeyeuudjeje
7 0
3 years ago
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