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mafiozo [28]
2 years ago
14

Two years ago, Erin was 35 inches tall. To ride the roller coaster at a theme park, she must be at least 42 inches tall. If she

was able to ride the roller coaster this year, how many inches did Erin grow?
Mathematics
2 answers:
luda_lava [24]2 years ago
6 0

Answer:

In two years erin grew 7 inches

Step-by-step explanation:

42 - 35 = 7

Nina [5.8K]2 years ago
4 0

Answer:

atleast 7 inches

Step-by-step explanation:

35 inches - 42 inches = 7 inches

Two years ago, Erin was 35 inches tall.

To ride the roller coaster at a theme park, she must be at least 42 inches tall. So that means she grew atleast 7 inches

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Answer:

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Step-by-step explanation:

Its the first model in purple. There are 6 students that represent a quarter of the class, so there is 6*4 = 24 students total.

5 0
3 years ago
Read 2 more answers
Round each addendum to the nearest ten. 478 + 112
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500 and 100 because if you see the seven right, seven is the judge and so as the one. Make it 500 and the next number 100. So you'll have en estimate of 600. Ur welcome.
8 0
3 years ago
Which expression is equivalent to StartRoot 120 x EndRoot?.
Irina-Kira [14]

Here for 120, the expression for the start root and end root is given  

\sqrt{120} =2\sqrt{30}

<h3>What will be the expression for start root and enroot of 120?</h3>

Here we need to find \sqrt{120}

By simplifying the given expression, we get:

120=2\times2\times2\times3\times5

120=(2^{2} )\times3\times5

by taking square roots on both sides we get

\sqrt{120} =2\sqrt{30}

Thus for 120, the expression for the start root and end root is given  \sqrt{120} =2\sqrt{30}

To know more about the Square roots follow

brainly.com/question/124481

5 0
2 years ago
The base of a triangle exceeds the height by 9 centimeters. If the area is 56 square centimeters, find the length of the base an
shepuryov [24]

Answer:

The height of the triangle is 7cm and the base is 16cm

Step-by-step explanation:

First of all we have to know the formula to calculate area of ​​a triangle

a = area = 56

b = base

h = heigth

a = (b * h)/2

we replace the known values and we make 2 equations

56cm² = (b * h)/2

b = h + 9cm

we replace b by (h + 9cm) in the first equation

56cm² = (h + 9cm * h)/2

56cm² * 2 = h² + 9h

0 = h² + 9h - 112cm²

we use bhaskara formula:

(-b (±) √ (b² - 4ac) ) / 2a

we replace with the known values

h = (-9 (±) √ (9² - 4*1*(-112) ) ) / 2*1

h = (-9 (±) √ (81 + 448) ) ) / 2

h = (-9 (±) √529) /2

h = (-9 (±) 23)/2

h1 = (-9 + 23) / 2

h1 = 14 / 2

h1 = 7

h2 = (-9 - 23) / 2

h2 = -32 / 2

h2 = -16

The height of the triangle is 7cm and the base is 16cm

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3 years ago
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