Question

Hurry!

Answer 1

Ans(a):

Given function is $f(x)=\frac{3x-1}{x+4}$

we know that any rational function is not defined when denominator is 0 so that means denominator x+4 can't be 0

so let's solve

x+4≠0 for x

x≠0-4

x≠-4

Hence at x=4, function can't have solution.

Ans(b):

We know that vertical shift occurs when we add something on the right side of function so vertical shift by 4 units means add 4 to f(x)

so we get:

g(x)=f(x)+4

$g(x)=\frac{3x-1}{x+4}+4$

We may simplify this equation but that is not compulsory.

Comparision:  

Graph of g(x) will be just 4 unit upward than graph of f(x).

Ans(c):

To find value of x when g(x)=8, just plug g(x)=8 in previous equation

$8=\frac{3x-1}{x+4}+4$

$8-4=\frac{3x-1}{x+4}$

$4=\frac{3x-1}{x+4}$

$4(x+4)=(3x-1)$

$4x+16=3x-1$

4x-3x=-1-16

x=-17

Hence final answer is x=-17