The value of gf(5) for the given two expressions is 135.
According to the question,
We have the following information:
f(x)= x +4
g(x) = 3x
Now, in order to find the value of gf(5), we will first find the value of gf.
Now, we will multiply these two expressions:
3x(x+4)
Now, the terms outside the brackets need to multiplied inside the bracket:
Now, we will put the value of x in this expression as 5 and solve the expression further by multiplication and addition:
3*5*5+12*5
75+60
135
Hence, the value of gf(5) for the given two expressions of f(x) and g(x) is 135.
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Suppose the number is y >>>>>So y/2 +2y/3 <14
multiply both sides by 6>>>>>>>>>. 6y/2 +6x2y/3 <14x6
3y + 4y < 84
7y <84
y <84/7
y < 12
Answer:
About 39 hours
Step-by-step explanation:
You would do 200/5.15 and get 38.83....
If you round then you get 39.
Answer:
Step-by-step explanation:
I must assume that you meant y = 7(6)^(x+2) + 1.
Please use " ^ " to indicate exponentiation. Thanks.
1) Graph y = 6^x first. Its y-intercept is (0, 1). It has a horizontal asymptote in y = 0. The graph starts in Quadrant II and progresses into Quadrant I, never touching or crossing the x-axis.
2) Stretch your graph vertically by a factor of 7.
3) Translate your resulting graph up by 1 unit.
4) Translate your graph 2 units to the LEFT.
To solve this problem, let us first find for the binary
equivalents of the numbers. They are:
Decimal --> Binary
+ 29 --> 00011101
+ 49 --> 00110001
- 29 --> 11100011
- 49 --> 11001111
Now we apply the normal binary arithmetic to these converted
numbers:
(+ 29) + (- 49) ---> 00011101 + 11001111 =
11101100 ---> - 20 (TRUE)
(- 29) + (+ 49) ---> 11100011 + 00110001 = 00010100
---> + 20 (TRUE)
(- 29) + (- 49) ---> 11100011 + 11001111 = 10110010
---> - 78 (TRUE)
