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3 years ago

PLEASE HELP ME WITH THIS GEOMETRY HW!! Let me know if I got my answers right and please help me with the blank ones

Mathematics

1 answer:

artcher [175]3 years ago

8 0

Step-by-step explanation:

Your answers for 1 and 2 are correct. MN and LN are both radii of the circle, and therefore equal. And NK can be found using Pythagorean theorem.

To find LP (and PM), we can use similar triangles:

LN / NK = LP / LK

10 / 26 = LP / 24

LP ≈ 9.23

PM ≈ 9.23

LM ≈ 2 × 9.23 = 18.46

To find NP, we can again use similar triangles.

NP / NL = NL / NK

NP / 10 = 10 / 26

NP ≈ 3.85

NQ is a radius of the circle, so it is equal to 10. PQ is therefore:

PQ ≈ 10 − 3.85 = 6.15

As you found, QK = 26 − 10 = 16.

Before we find LR, let's find RK using similar triangles.

RK / QK = NK / LK

RK / 16 = 26 / 24

RK ≈ 17.33

LR ≈ 24 − 17.33 = 6.67

As you found, MK = 24.

And finally, MS = LR ≈ 6.67.

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2 years ago

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Researchers are interested if a school breakfast program leads to taller children. Assume that the population of all 5 year-old

DedPeter [7]

Answer:

$39-1.96\frac{1}{\sqrt{25}}=38.608$

$39+1.96\frac{1}{\sqrt{25}}=39.392$

So on this case the 95% confidence interval would be given by (38.608;39.392)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=39$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=1$ represent the population standard deviation

n=25 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The margin of error is given by:

$ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$