When you compare two functions f(x) and g(x), you're looking for a special input 
such that
Since you have the table with some possible candidates for , you simply have to choose the row that gives values for f(x) and g(x) that are as close as possible (the exact solution would give the same value for f(x) and g(x), so the approximate solution will give values for f(x) and g(x) that are close to each other).
In your table, the values for f(x) and g(x) are closer when x=-0.75
Answer:
chicken
Step-by-step explanation:
Answer:
Continuous: g(x) and j(x)
Removable: h(x) and m(x)
Infinite: f(x) and i(x) and k(x)
Jump: l(x)
Step-by-step explanation:
In this question a vital information has been provided. This information can be used for determining the answer to the question that is asked. It is given that 120% of a certain number is 360 pound. The 100% value of the number needs to be determined.
Let us assume the number to be = x
Then
120x/100 = 360
12x/10 = 360
12x = 360 * 10
12x = 3600
x = 3600/12
= 300
Now we can say that the 100% of the number or the actual number is 300 pounds. I hope the problem is clear to you and you can understand the trick involved in the question.
219+159≤x≤369+309
The answer can then be simplified to
378≤x≤678
