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juin [17]
3 years ago
15

What is the median for this data set?

Mathematics
1 answer:
Sever21 [200]3 years ago
8 0
The meridian for this set is 3.005 (option C)

Note ➡The word Median is lime the "average" for all of the values of the particular problem
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The product of eight and a number x
Julli [10]

Answer:

To write this down as an algebraic expression you would simply need to multiply the two terms together.

So in this case it would be 8 multiples by x which is 8x

Step-by-step explanation:

1) Find out the variables in the Expression

2) Find the operation that is done to the variables

3) Apply the operation to those variables.

8 0
3 years ago
Lol yeah i need a answer:)
GarryVolchara [31]

It is 175/30. (C) the third option.
3 0
3 years ago
Given the literal equation ab/a+b = c , with b = –1 + a, what is the value of c if a = 5?
Nesterboy [21]

The solution would be like this for this specific problem:

ab/a+b = c 

b = -1 + a

for c:
<span>(5(-1 + 5))/(5 + (-1 +5))
</span><span>5(4)/ 5 + 4
</span><span>20 / 9
</span>

<span>The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>



3 0
3 years ago
Read 2 more answers
The number of perfect squares fro 4 to 50 is​
Grace [21]

Step-by-step explanation:

4, 9, 16, 25, 36,49

there are 6 perfect squares from 4 to 50

8 0
3 years ago
Read 2 more answers
Which property justifies the following statement? If 13x 104 then x 8.
gogolik [260]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices that can be found from other source:

A. division property of equality 
<span>B. Reflexive property of equality </span>
<span>C. Substraction property of equality </span>
<span>D. Multiplication property of equality
</span>
The answer is <span>D. Multiplication property of equality</span>
4 0
3 years ago
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