Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=
![\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-b%2B%2F-%20%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%20%7D%7B2a%7D%20)
a=-0.04
b=8.3
c=4.3
x=
![\frac{-8.3+/- \sqrt{8.3^{2}-4(-0.04)(8.3)} }{2(-0.04)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-8.3%2B%2F-%20%5Csqrt%7B8.3%5E%7B2%7D-4%28-0.04%29%288.3%29%7D%20%7D%7B2%28-0.04%29%7D%20)
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
You cannot simplify this but you can factorise it:
9x^6 (x^2 - 2)
Answer:
6 x 10= 60
60/2=30
Answer is<u> 30</u> i think
Step-by-step explanation:
6000 - 3672 = 2328
Just use a calculator my friend :)